<span>B) the bisectors of angles D, E, and F
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In an inscribed circle of a triangle, all angle bisectors will pass through the center of the circle.
Pls. see attachment.
1st attachment is Triangle DEF. 2nd attachment is how inscribed circle relates to the triangle it is inscribed in.
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Formula
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Area of circle = πr²
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Find radius
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πr² = 75
r² = 75 ÷ π
r² = 23.87
r = √23.87
r = 4.89 cm (nearest hundreds)
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Answer : radius = 4.89cm
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Answer:
#4: -18xy^3z * sqrt(z)
#5: 24xy^3 * sqrt 3(x^2)
Step-by-step explanation:
#4: -2*sqrt(9^2 * x^2 * y^2 * y^2 * y^2 * z^2 * z)
You can cancel if there is a number sqaured
-2 * 9 * x * y * y * y * z * sqrt(z)
-18xy^3z * sqrt(z)
#5: 6 * sqrt 3( 4^3 * x^3 * x^2 * (y^3)^3 )
You can cancel if the number is cubed.
6 * 4 * x * y^3 * sqrt 3( x^2 )
24xy^3 * sqrt 3(x^2)
Answer:
The locations of E' and F' are E'(-2,0) and F'(0,1), and lines g and g' are parallel.
Step-by-step explanation:
I got it right on my test! :)
A) 276 / 138 = 2
B) 26/2 = 13, 13/2 = 6.5
Answer is B