Answer:
b
Step-by-step explanation:
Answer:


<u>Group the Variable's</u>:
2 x - 5 + 7 y - 3 = 9 x - 1 - y -8
2x -9x + 7y +y = -1 -8 +5 + 3
-7x + 8y = -1
<u><em>From this find x and y</em></u>
<u>For X</u>
-7x + 8y = -1
-7x = -1 -8y
7x = 8y + 1
x = (8y +1)/7
<u>For Y</u>
-7x + 8y = -1
8y = -1 +7x
y = (7x -1)/8
Answer:
That would equal
or approximately 0.67. If this helps, please rank Brainliest. Thanks!
Given:
The cost C (in dollars) to participate in a ski club is given by,

Where x is the number of ski trips we take.
To find:
The number of ski trips when a total cost of $315 and $485 is spent.
Explanation:
Substituting C = 315 in the given equation we get,

Substituting C = 485 in the given equation we get,

Thus,
If we spend a total cost of $315, we can take 3 ski trips.
If we spend a total cost of $485, we can take 5 ski trips.
Final answer:
• If we spend a total cost of $315, we can take 3 ski trips.
,
• If we spend a total cost of $485, we can take 5 ski trips.
if we have a number like say hmm 4, and we say hmmm √4 is ±2, it simply means, that if we multiply that number twice by itself, we get what's inside the root, we get the 4, so (+2)(+2) = 4, and (-2)(-2) = 4, recall that <u>minus times minus = plus</u>.
so, any when we're referring to even roots like
, the positive number, that can multiply itself an even amount of times, will produce a valid value, BUT the negative number that multiply itself an even amount of times, will also produce a valid value.
now, that's is not true for odd roots like
, because the multiplication of the negative number will not produce a valid value, let's put two examples on that.
![\bf \sqrt[3]{27}\implies \sqrt[3]{3^3}\implies 3\qquad because\qquad (3)(3)(3)=27 \\\\\\ however\qquad (-3)(-3)(-3)\ne 27~\hspace{8em}(-3)(-3)(-3)=-27 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \sqrt[3]{-125}\implies \sqrt[3]{-5^3}\implies -5\qquad because\qquad (-5)(-5)(-5)=-125 \\\\\\ however\qquad (5)(5)(5)\ne -125~\hspace{10em}(5)(5)(5)=125](https://tex.z-dn.net/?f=%5Cbf%20%5Csqrt%5B3%5D%7B27%7D%5Cimplies%20%5Csqrt%5B3%5D%7B3%5E3%7D%5Cimplies%203%5Cqquad%20because%5Cqquad%20%283%29%283%29%283%29%3D27%0A%5C%5C%5C%5C%5C%5C%0Ahowever%5Cqquad%20%28-3%29%28-3%29%28-3%29%5Cne%2027~%5Chspace%7B8em%7D%28-3%29%28-3%29%28-3%29%3D-27%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%0A%5Csqrt%5B3%5D%7B-125%7D%5Cimplies%20%5Csqrt%5B3%5D%7B-5%5E3%7D%5Cimplies%20-5%5Cqquad%20because%5Cqquad%20%28-5%29%28-5%29%28-5%29%3D-125%0A%5C%5C%5C%5C%5C%5C%0Ahowever%5Cqquad%20%285%29%285%29%285%29%5Cne%20-125~%5Chspace%7B10em%7D%285%29%285%29%285%29%3D125)
so, when the root is an odd root, you will always get only one number that will produce the radicand.