The speed of the target with the bullet lodged in it is 5.6 m/s.
<h3>What is speed?</h3>
This is the rate of change of distance.
To calculate the speed of the target and the bullet lodged, we use the formula below.
Formula:
- V = mu/(m+M)............. Equation 1
Where:
- V = Speed of the target and the bullet
- m = mass of the bullet
- M = mass of the target
- u = Initial speed of the target
From the question,
Given:
- m = 0.04 kg
- u = 1400 m/s
- M = 9.96 kg
Substitute these values into equation 1
- V = (0.04×1400)/(0.04+9.96)
- V = 56/10
- V = 5.6 m/s
Hence, the speed of the target with the bullet lodged in it is 5.6 m/s.
Learn more about speed here: brainly.com/question/6504879
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Answer:
Explanation:
Given that
Q= 5 L/min
1 L = 10⁻³ m³/s
1 min = 60 s
Q=0.083 x 10⁻³ m³/s
d= 6 μm
v= 1 mm/s
So the discharge flow through one tube
q = A v
A=2.8 x 10⁻¹¹ m²
v= 1 x 10⁻³ m/s
q= 2.8 x 10⁻¹⁴ m³/s
Lets take total number of tube is n
Q= n q
n=Q/q
Surface area A
A= π d L
Explanation:
A particular kind of matter with uniform properties..
Ionic bonding is the bonding between a positive metal with a negative nonmetal (metals are always positive while non metals are opposite). The meeting of a metal with a non metal creates an ionic bond.
