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Phantasy [73]
3 years ago
13

For the common-emitter, common-base and emitter-follower amplifier designs,what is the primary benefit of each amplifier?

Physics
1 answer:
kati45 [8]3 years ago
6 0

Answer:

Explanation:

A common emitter amplifier works by inverting. It does have low input impedance. Despite its low input impedance, it poses an otherwise high output impedance.

The common base circuit performs optimally when it acts as a current buffer. It has the ability to take an input current at a low input impedance, and transmit almost the same current to an impedance with a higher output

The primary benefit of emitter follower amplifier is that the transistor is able to provide current and power gain. Although this transistor takes in little current from the input. It still provides an impedance with a low output to a circuit by exercising the output of the follower. This then translates to that the output under load not dropping.

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An individual is nearsighted; his near point is 13.0 cm and his far point is 50.4 cm. what lens power is needed to correct his n
Colt1911 [192]

Answer:

= -1.984 Diopters

Explanation:

The lens should form an upright, virtual image at the far point.

Therefore;

The image distance, V will be -50.4 cm, since the image is virtual.

For objects at very far distant the object distance,u, will be ∞ ; This means that focal length, f, will be equivalent to image distance, v, that is -50.4 cm

Therefore; f = -50.4/100 = -0.504 m

But, since Power of a lens, P, is given by the reciprocal of focal length in meters, (1/f)

Then, power will be given by;

Power = 1/f

           = 1/-0.504 m

           =- 1.984

Power is measured in Diopters

Hence          <u>= -1.984 Diopters</u>

5 0
3 years ago
At this radius, what is the magnitude of the net force that maintains circular motion exerted on the pilot by the seat belts, th
Ainat [17]

Answer:

Fc=5253 N

Explanation:

Answer:

Fc=5253 N

Explanation:

sequel to the question given, this question would have taken precedence:

"The 86.0 kg pilot does not want the centripetal acceleration to exceed 6.23 times free-fall acceleration. a) Find the minimum radius of the plane’s path. Answer in units of m."

so we derive centripetal acceleration first

ac (centripetal acceleration) = v^2/r

make r the subject of the equation

r= v^2/ac

 ac is 6.23*g which is 9.81

v is 101m/s

substituing the parameters into the equation, to get the radius

(101^2)/(6.23*9.81) = 167m

Now for part

( b) there are two forces namely, the centripetal and the weight of the pilot, but the seat is exerting the same force back due to newtons third law.

he net force that maintains circular motion exerted on the pilot by the seat belts, the friction against the seat, and so forth is the centripetal force.

Fc (Centripetal Force) = m*v^2/r  

So (86kg* 101^2)/(167) =

Fc=5253 N

4 0
4 years ago
_______ is energy that is transferred due to a difference in temperatures.
SVEN [57.7K]

Answer:

C. Heat

Explanation:

HEAT is energy that is transferred due to a difference in temperatures.

I hope it helps! Have a great day!

6 0
2 years ago
Dez pours water (n 1.333) into a container made of crown glass (n 1.52). The light ray in ner made of crown glass (n = 1.52). Th
siniylev [52]

Answer:

The angle of the corresponding refracted ray is 34.84°

Explanation:

Given that,

Refractive index of water n= 1.33

Refractive index of glass n= 1.52

Incident angle = 30.0°

We need to calculate the refracted angle

Using formula of Snell's law

n_{i}\sin i=n_{r}\sin r

Put the value into the formula

\sin r=\dfrac{n_{i}\sin i}{n_{r}}

\sin r=\dfrac{1.52\times\sin30}{1.33}

\sin r=0.5714

r=sin^{-1}0.5714

r = 34.84^{\circ}

Hence, The angle of the corresponding refracted ray is 34.84°

8 0
4 years ago
The acceleration due to gravity vector is always in the ____ direction.
finlep [7]
It goes in the downward direction
4 0
3 years ago
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