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3 years ago

For the common-emitter, common-base and emitter-follower amplifier designs,what is the primary benefit of each amplifier?

Physics

1 answer:

kati45 [8]3 years ago

6 0

Answer:

Explanation:

A common emitter amplifier works by inverting. It does have low input impedance. Despite its low input impedance, it poses an otherwise high output impedance.

The common base circuit performs optimally when it acts as a current buffer. It has the ability to take an input current at a low input impedance, and transmit almost the same current to an impedance with a higher output

The primary benefit of emitter follower amplifier is that the transistor is able to provide current and power gain. Although this transistor takes in little current from the input. It still provides an impedance with a low output to a circuit by exercising the output of the follower. This then translates to that the output under load not dropping.

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If you push a 200 kg box with a horizontal force of 1,172 N and kinetic friction resists the motion with a force of 962 N, what

Lynna [10]

Answer:

a = 1.05m.s²

Explanation:

Fnet = m×a

Fapplied - friction = m×a

1172 - 962 = 200 × a

210 = 200a

a = 1.05

5 0

2 years ago

The amount of matter in an object is called its

Serga [27]

The amount of matter in an object is called its, mass. How much the mass weights would be referred to as weight

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3 years ago

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Consider a 2.54-cm-diameter power line for which the potential difference from the ground, 19.6 m below, to the power line is 11

tiny-mole [99]

Answer:

The line charge density is $1.59\times10^{-4}\ C/m$

Explanation:

Given that,

Diameter = 2.54 cm

Distance = 19.6 m

Potential difference = 115 kV

We need to calculate the line charge density

Using formula of potential difference

$V=EA$

$V=\dfrac{\lambda}{2\pi\epsilon_{0}r}\times\pi r^2$

$\lambda=\dfrac{V\times2\epsilon_{0}}{r}$

Where, r = radius

V = potential difference

Put the value into the formula

$\lambda=\dfrac{115\times10^{3}\times2\times8.8\times10^{-12}}{1.27\times10^{-2}}$

$\lambda=1.59\times10^{-4}\ C/m$

Hence, The line charge density is $1.59\times10^{-4}\ C/m$

4 0

3 years ago

our iclicker operates at a frequency of approximately 900 mhz (900x106 hz). what is the approximate wavelength of the em wave pr

Elena-2011 [213]

wavelength of the EM wave produced by your iclicker is 0.33 m.

<h3>What makes an EM wave?</h3>

When an electric field (illustrated in red arrows) combines with a magnetic field, electromagnetic waves are generated (which is shown in blue arrows). An electromagnetic wave's magnetic and electric fields are perpendicular to each other and to the wave's direction.
A changing magnetic field causes a changing electric field, and vice versa—the two are inextricably related. Electromagnetic waves are created by changing fields. Electromagnetic waves, unlike mechanical waves, do not require a medium to propagate.

The clicker emits EM (electromagnetic) wave which travels at the speed of light, that is

v = 3 x 10⁸ m/s

The frequency is

f = 900mHz = 9 x 10⁸ Hz

velocity = frequency * wavelength, the wavelength, λ, is given by

fλ = v

λ = v/f

= (3 x 10⁸ m/s) / (9 x 10⁸ 1/s)

= 1/3 m = 0.333 m

To learn more about electromagnetic waves refer,

brainly.com/question/25847009

#SPJ1

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1 year ago

Q: A: Sarah and Maria made a telephone using two cans and a string. It was a very long string. Maria went upstairs in her house

GrogVix [38]

This contraption is a lot of fun, and you really should try it
some time.

The sound waves move from one can to the other one
by traveling through the string.

3 0

3 years ago

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