Answer:
The time of Mars is 1.65 times larger on Mars than on Earth
Explanation:
The equation that describes the system is the final speed is equal to the speed minos the speed lost by the collision with the porhole
Vf = Vo - V pothole
B) let's transform the weight of free groin system and N international system
1 N = 0.2248 lb
2.8 lbs (1N / 0.2248lbs) = 12.5 N
c) Kinematic equations are the same in all inertial systems, Mars and Earth, so we can use the height equation, with zero initial velocity
Y = Vo t - ½ g t²
Y = - ½ g t²
t = √ 2Y / g
Mars
gm = 0.37g
gm = 0.37 9.8
gm = 3,626 m / s²
t = √( 2 1.9 / 3.626
)
t = 1.02 s
Earth
t = √( 2 1.9 / 9.8)
t = 0.62 s
To make the comparison of time we are the relationship between the two
tm / te = 1.02 / 0.62
tm / te = 1.65
The time of Mars is 1.65 times larger on Mars than on Earth
The shot putter should get out of the way before the ball returns to the launch position.
Assume that the launch height is the reference height of zero.
u = 11.0 m/s, upward launch velocity.
g = 9.8 m/s², acceleration due to gravity.
The time when the ball is at the reference position (of zero) is given by
ut - (1/2)gt² = 0
11t - 0.5*9.8t² = 0
t(11 - 4.9t) = 0
t = 0 or t = 4.9/11 = 0.45 s
t = 0 corresponds to when the ball is launched.
t = 0.45 corresponds to when the ball returns to the launch position.
Answer: 0.45 s
Answer: 3
Explanation:
Given
One cloud is traveling at rate of 
combined velocity of the two is 
Suppose the masses of the clouds be 
Conserving momentum

Answer:
Approximately
.
Explanation:
Cathode is where reduction takes place and anode is where oxidation takes place. The potential of a electrochemical reaction (
) is equal to
.
There are two half-reactions in this question.
and
. Either could be the cathode (while the other acts as the anode.) However, for the reaction to be spontaneous, the value of
should be positive.
In this case,
is positive only if
is the reaction takes place at the cathode. The net reaction would be
.
Its cell potential would be equal to
.
The maximum amount of electrical energy possible (under standard conditions) is equal to the free energy of this reaction:
,
where
is the number moles of electrons transferred for each mole of the reaction. In this case the value of
is
as in the half-reactions.
is Faraday's Constant (approximately
.)
.