Answer:
I dont see a picture where is it?
Explanation:
I cannot see anything L question Luestion
Answer:
Continental polar (cP) or continental arctic (cA) air masses are cold, dry, and stable. These air masses originate over northern Canada and Alaska as a result of radiational cooling. Maritime polar (mP) air masses are cool, moist, and unstable.
Explanation:
Answer:

Explanation:
Using Kepler's third law, we can relate the orbital periods of the planets and their average distances from the Sun, as follows:

Where
and
are the orbital periods of Mercury and Earth respectively. We have
and
. Replacing this and solving for

The force of attraction between two objects Mass and distance.
<h3>What is newton's law of gravitation?</h3>
Every particle in the cosmos attracts every other particle with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centres, according to Newton's law of universal gravitation.
Inductive reasoning, as described by Isaac Newton, was used to deduce this general physical law from actual facts. It was created by Newton and is a component of classical mechanics. Philosophiae Naturalis Principia Mathematica, also known as "the Principia," was originally published on July 5, 1687. In April 1686, when Newton gave Book 1 of the unpublished book to the Royal Society, Robert Hooke said that Newton had learned the inverse square law from him.
According to the law, every point mass attracts every other point mass when a force applies along the line that intersects the two points, in today's parlance. The force is inversely equal to the square of the separation between the masses and directly proportional to their product.

to learn more about newton's law of gravitation go to - brainly.com/question/9373839
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Answer:
22kj
Explanation:
set h = 0 at the end of slide.
final height is -12m
initial condition will be Ui = 0
Ki = 1/2mv² = 1/2 x 61 x (27)² = 22234.5J
Final condition is Ui = mgh = 61 x 9.8 x -12 = -7173J
Ki = 1/2mv²
Ki= 1/2 x 61 x (16)² = 7808J
conservation energy says that
Ui + Ki = Uf +Kf +ΔEth
so ΔEth = Ui + Ki - Uf - Kf
ΔEth = 22234.5 - 7808 + 7173
ΔEth = 21600J
ΔEth =22Kj