$\begin{equation*} \begin{pmatrix}a+7 & 2z+1 & 3m \\6k & 5 & 1\end{pmatrix} + \begin{pmatrix}12a & 6z & 5m \\7k & 4 & 2\end{pmatrix} = \begin{pmatrix}33 & 39 & 32 \\39 & 9 & 3\end{pmatrix} \end{equation*}$

In Matrix Addition, each element in corresponding position is added.

In Matrix Equality, elements in the same position are equal.

Applying these two principles

a+7+12a=33

13a=33-7

13a=26

a=2

2z+1+6z=39

8z=39-1

8z=38

z= 4.75

3m+5m=32

8m=32

m=4

6k+7k=39

13k=39

k=3

Therefore:

a=2, z= 4.75, m=4, k=3

5 0

3 years ago

Which is a list of all the zeros of x^5 + 7x^4 = 18x³?

Andrei [34K]

Answer:

Step-by-step explanation:

Because there is three numbers

3 0

3 years ago

What is the theorem that states a perpendicular line to the hypotenuse splits the triangle into two similar right triangles?

iogann1982 [59]

Answer:Pythagoras

Step-by-step explanation:

5 0

3 years ago

In a quadrilateral, three of the angles are obtuse. Which of the following could not be the angle measure of the fourth angle?

Luba_88 [7]

If an angle it is obtuse it is between 90 and 180.

Angles in a quadrilateral add up to 360.

Therefore 3 obtuse angles must add up to AT LEAST 273 and if you then added the 90 it would get you to 363 which is too large so it cant be 90 :)

3 0

3 years ago