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lina2011 [118]
3 years ago
6

What is the charge for the cation in AgBr

Chemistry
1 answer:
Westkost [7]3 years ago
8 0
The correct answer is Ag
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Jimmy's Chemical reaction/ Recipe for making Grilled chese sandwiches is given below: 1 slice of cheese + 2 slices of bread = 1
Juli2301 [7.4K]

Answer:

See explanation

Explanation:

We have been told in the question that the equation of the reaction is; 1 slice of cheese + 2 slices of bread = 1 Grilled cheese sandwich ( mole ratio is, 1:2:1) .

Then the reagents are 10 slices of cheese 30 slices of bread. It then follows that 10 slices of cheese should be combined with 20 slices of bread according to the mole ratio.

However, we have 30 slices of bread and 10 slices of cheese so cheese is the limiting reactant while bread is the reactant in excess.

Yes, the number of glilled chese sandwishes he can make is decided by the limiting reactant because it gets used up most.

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3 years ago
Which type of radioactive decay occurs in the following reaction?
ella [17]
This one is beta decay (the -1 subscript tells us that)
7 0
4 years ago
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Veronica is taking an average of 16 height measurements in a brand-new experiment. Which term is this the best example of? repli
Karolina [17]

Answer:

repetition

Explanation:

Taking an average of 16 height measurements is an example of repetition. Repetition involves making and taking repeated measurements in an experiment.

The goal is to achieve a highly accurate and precise data from the experiment.

  • Replication involves duplicating another experiment and testing to see how valid they are.
  • Since Veronica's experiment is a brand new one, it's hypothesis has not been tested or replicated in any way.
  • Therefore, it is not a replication.
  • But she is repeating the experiment to obtain different values.
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An element has an atomic number of 27. How many protons and electrons are in a neutral atom of the element
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27 and 32

Explanation:

3 0
2 years ago
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Se hace reaccionar 4,00 g de aluminio y 42,00 g de bromo, según la reacción: Al(s)+Br2(l)⟶AlBr3(s) Calcular las moles de AlBr3(s
NeX [460]

Answer:

0.145 moles de AlBr3.

Explanation:

¡Hola!

En este caso, al considerar la reacción química dada:

Al(s)+Br2(l)⟶AlBr3(s)

Es claro que primero debemos balancearla como se muestra a continuación:

2Al(s)+3Br2(l)⟶2AlBr3(s)

Así, calculamos las moles del producto AlBr3 por medio de las masas de ambos reactivos, con el fin de decidir el resultado correcto:

n_{AlBr_3}^{por\ Al}=4.00gAl*\frac{1molAl}{27gAl} *\frac{2molAlBr_3}{2molAl}=0.145mol AlBr_3\\\\n_{AlBr_3}^{por\ Br_2}=42.00gr*\frac{1molr}{160g Br_2} *\frac{2molAlBr_3}{3molBr_2}=0.175mol AlBr_3

Así, inferimos que el valor correcto es 0.145 moles de AlBr3, dado que viene del reactivo límite que es el aluminio.

¡Saludos!

3 0
3 years ago
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