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2 years ago

15

Element X reacts with chlorine to form an ionic compound that has the formula XCl₂. To which group on the Periodic Table could e

lement X belong?

1 answer:

marishachu [46]2 years ago

4 0

Answer:

<u>Group 2 is the correct answer.</u>

Explanation:

<u>Chlorine has a charge -1. It means that X is +2 so that the formula is XCl2. </u>

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How does changing the initial temperature of the copper affect how much heat energy it has?

taurus [48]

Answer:

the rock has a greater amount of heat energy which transfers to water causing vaporization.

5 0

1 year ago

The density of water at 4 degrees Celsius is 1.00 g/cm cubed at unknown object has density of 7.9 g/cm cubed would you expect it

NNADVOKAT [17]

Answer:

The object will be sank

Explanation:

In this case the object is more dense than water.

Density is the relationship between a certain amount of mass of matter and the volume that is being occupied by it.

The object occupies more volume, so it occupies more mass.

As the mass from the object is higher, the object will be sank because the weight is higher than the weight from the liquid.

If the object has a lower density than the water, it will float on it.

7 0

2 years ago

The elementary reaction 2H2O(g)↽−−⇀2H2(g)+O2(g) 2H2O(g)↽−−⇀2H2(g)+O2(g) proceeds at a certain temperature until the partial pres

Dima020 [189]

Answer:

$6.25\times 10^{-6}$ is the value of the equilibrium constant at this temperature.

Explanation:

Equilibrium constant in terms of partial pressure is defined as the ratio of partial pressures of products to the partial pressures of reactants each raised to the power equal to their stoichiometric ratios. It is expressed as $K_{p}$

$2H_2O(g)\rightleftharpoons 2H_2(g)+O_2(g)$

Partial pressures at equilibrium:

$p^o_{H_2O}=0.070 atm$

$p^o_{H_2}=0.0035 atm$

$p^o_{O_2}=0.0025 atm$

The equilibrium constant in terms of pressures is given as:

$K_p=\frac{(p^o_{H_2})^2\times (p^o_{O_2})}{(p^o_{H_2O})62}$

$K_p=\frac{(0.0035 atm)^2\times 0.0025 atm}{(0.070 atm)^2}=6.25\times 10^{-6}$

$6.25\times 10^{-6}$ is the value of the equilibrium constant at this temperature.

5 0

2 years ago

Does anyone know how to do this?

mr Goodwill [35]

Answer:

this look hard

Explanation:

hmm

4 0

2 years ago

PLEASE HELP ME<br><br> what would be the mass of 9.03 x 1021 molecules of hydrobromic acid (HBr)?

Nikitich [7]

We know 1 mole of any atom or molecules contains $6.033 \times 10^{23}$ atom or molecules.

1 mole of HBr i.e 81 gm/mol contains $6.033 \times 10^{23}$ atom or molecules.

So, mass of $9.03\times 10^{21}$ molecules is :

$m=\dfrac{81\times 9.03\times 10^{21} }{6.033 \times 10^{23}}\\\\m= 1.21\ gm$

Therefore, mass of $9.03\times 10^{21}$ molecules is 1.21 gm .

Hence, this is the required solution.

7 0

2 years ago