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KatRina [158]
2 years ago
6

Write a paragraph (5-7 sentences) describing pH and conductivity.

Chemistry
1 answer:
PilotLPTM [1.2K]2 years ago
4 0

Answer:

pH is a measure of hydrogen ion concentration, a measure of the acidity or alkalinity of a solution. The pH scale usually ranges from 0 to 14. Aqueous solutions at 25°C with a pH less than 7 are acidic, while those with a pH greater than 7 are basic or alkaline. A pH level of 7.0 at 25°C is defined as "neutral" because the concentration of H3O+ equals the concentration of OH− in pure water. On the other hand, electrical conductivity is a non-specific measurement of the concentration of both positively and negatively charged ions within a sample. So the short answer to the question is as follows, the presence of any hydrogen ions present in a substance will impact the pH level and most probably influence conductivity levels. However, hydrogen ions make up only a small part of the ion concentration measured by a conductivity meter.

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10g of a non-volatile and non-dissociating solute is dissolved in 200g of benzene.
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<u>Answer: </u>The molar mass of solute is 115 g/mol.

<u>Explanation:</u>

Elevation in the boiling point is defined as the difference between the boiling point of the solution and the boiling point of the pure solvent.

The expression for the calculation of elevation in boiling point is:

\text{Boiling point of solution}-\text{boiling point of pure solvent}=i\times K_b\times m

OR

\text{Boiling point of solution}-\text{Boiling point of pure solvent}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times w_{solvent}\text{(in g)}} ......(1)

where,

Boiling point of pure solvent (benzene) = 80.10^oC

Boiling point of solution = 81.20^oC

i = Vant Hoff factor = 1 (for non-electrolytes)

K_b = Boiling point elevation constant = 2.53^oC/m

m_{solute} = Given mass of solute = 10 g

M_{solute} = Molar mass of solute = ? g/mol

w_{solvent} = Mass of solvent = 200 g

Putting values in equation 1, we get:

81.20-80.10=1\times 2.53\times \frac{10\times 1000}{M_{solute}\times 200}\\\\M_{solute}=\frac{1\times 2.53\times 10\times 1000}{1.1\times 200}\\\\M_{solute}=115g/mol

Hence, the molar mass of solute is 115 g/mol.

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Explanation:

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