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KonstantinChe [14]
3 years ago
14

The term PVC used in the plastic industry stands for

Chemistry
1 answer:
Phantasy [73]3 years ago
5 0
Polyvinyl Chloride.       
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Explain how your brain and sensory organs get information from the outside world
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Your brain has about 100 billion neurons, all of which are interneurons. Each of these neurons may receive up to 10,000 messages from other neurons and may send messages to about 1,000 more. Every day, billions of nerve impulses travel through your nervous system from neuron to other neurons or body structures. The place where a neuron transfers an impulse to another structure is called a synapse. At the axon tips, electrical signals carried through the neuron change into a chemical form. This change allows the message to cross the gap. The message then continues in electrical from through the next neuron.
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- What part of the ocean absorbs a large amount of solar energy?
GrogVix [38]

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artic ocean

Explanation:

8 0
3 years ago
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In an accident, a solution containing 2.5 kg of nitric acid was spilled. Two kilograms of Na2CO3 was quickly spread on the area
storchak [24]

First we must write a balanced chemical equation for this reaction

Na_2CO_3 _(_a_q_)+ 2HNO_3_(_a_q_) \implies 2NaNO_3_(_s_) + CO_2_(_g_) + H_2O_(_l_)

The mole ratio for the reaction between HNO_3 and Na_2CO_3 is 1:2. This means 1 moles of Na_2CO_3 will neutralize 2 moles HNO_3. Now we find the moles of each reactant based on the mass and molar mass.

2500g HNO_3 \times \frac{mol}{63.01g\ HNO_3} = 39.67 mol\ HNO_3

2000g\ Na_2CO_3 \times \frac{mol}{105.99g \ Na_2CO_3} = 18.87 mol\ Na_2CO_3

\frac{18.87 mol Na_2CO_3}{39.67\ HNO_3} = \frac{1 molNa_2CO_3}{2 mol HNO_3}

The Na_2CO_3 was enough to neutralize the acid because 18.87:39.67 is the same as 1:2 mol ratio.

4 0
4 years ago
Would it be D....????<br> HELPPPPPP
AlekseyPX

Answer:

yes

Explanation:

6 0
4 years ago
What is the mass of sodium (Na) in 50 grams of table salt (NaCl)? Show your work.
Anvisha [2.4K]

Answer:

19 g

Explanation:

Data Given:

Sodium Chloride (table salt) = 50 g

Amount of sodium (Na) = ?

Solution:

Molecular weight calculation:

NaCl = 23 + 35.5

NaCl = 58.5 g/mol

Mass contributed by Sodium = 23 g

calculate the mole percent composition of sodium (Na) in sodium Chloride.

Since the percentage of compound is 100

So,

                 Percent composition of sodium (Na) = 23 / 58.5 x 100

                  Percent of sodium (Na) = 39.3 %

It means that for ever gram of sodium chloride there is 0.393 g of Na is present.

So,

for the 50 grams of table salt (NaCl) the mass of Na will be

              mass of sodium (Na) = 0.393 x 50 g

              mass of sodium (Na) = 19 g

6 0
4 years ago
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