3x + 2y = 4<br> 4x + 3y = 7

The following data was collected to explore how the average number of hours a student studies per night and the student's GPA af

Alja [10]

Answer:

Step-by-step explanation:

Hello!

The given data is for multiple regression with two independent variables:

Y= α + β₁X₁ + β₂X₂

Y: ACT score of a student

X₁: Number of hours spent studying.

X₂: Student's GPA

Effects on ACT Scores

Study Hours GPA ACT Score

6 2 31

3 4 28

5 2 19

2 4 29

2 4 20

Using a statistical software I've estimated the regression line:

Y= -37.57 + 7.14X₁ + 11.64X₂

1)Find the p-value for the regression equation that fits the given data. Round your answer to four decimal places.

The p-value for the multiple regression (One-Tailed F-test-ANOVA-) is 0.5045

2)Determine if a statistically significant linear relationship exists between the independent and dependent variables at the 0.01 level of significance. If the relationship is statistically significant, identify the multiple regression equation that best fits the data, rounding the answers to three decimal places. Otherwise, it indicates that there is not enough evidence to show that the relationship is statistically significant.

The hypotheses for the multiple regression is:

H₀: β₁ = β₂ = 0

H₁: At least one βi≠0 ∀ i=1, 2

α: 0.01

Since the p-value= 0.5045 is greater than α: 0.0, the decision is to not reject the null hypothesis, this means that there is no significant evidence to say that there is a relationship between the ACT scores and the student's GPA and hours that the student spent studying.

The individual tests are:

(remember to have validity the individual tests should be made at the same α level)

H₀: β₁ = 0

H₁: β₁ ≠ 0

α: 0.01

ANOVA: p-value: 0.2977

The decision is to not reject the null hypothesis.

At a level of 1%, there is no evidence to support the hypothesis that the number of hours spent by studying doesn't modify the average ACT of students.

H₀: β₂ = 0

H₁: β₂ ≠ 0

α: 0.01

ANOVA: p-value: 0.3038

The decision is to not reject the null hypothesis.

At a level of 1%, there is no evidence to support the hypothesis that the student's GPA doesn't modify the average ACT of students.

None of the independent variables, together or individually, are effective to explain the variability of the ACT scores of the students in the study.

I hope this helps!

6 0

3 years ago

2n 3 + 4n 2 - 7 and -n 3 + 8n - 9 what is the sum

Art [367]

N^3 +4n^2 +8n -16
hope it help
mark me brainliest if i right ty

8 0

4 years ago

Read 2 more answers

PLEASEEEEEEEEEEEEEEEEEEEEEEE

pshichka [43]

Answer:

9

hope this helps

have a good day :)

Step-by-step explanation:

6 0

3 years ago

2 questions ples answer

OverLord2011 [107]

1. We are given:
$a^2 = 64$

The only a which squared gives you 64 is 8. The perimeter of an 8 by 8 square will be 32. Half of that is 16. Now, let's see what we can do. We can set up:
$4a = 16$

Obviously, each side length has to be 4. So, the area of this square will be 16 units².

2. Let n equal her son's age. So, her age right now will be (S = her age):
$S = 18n$
1 year ago it was:
$S-1 = 3n$

We have 2 equations, let's substitute. We can rewrite this as:
$18n-1 = 3n$
Solve for n:
$15n-1=0$
$n= \frac{1}{15}$

We know the value of n, which is her son's age. So, her son is 1/15 of a year old or about 24 days old.

8 0

4 years ago

Megan has 25 phone numbers stored in her cell phone. Abby has some phone numbers stored in her cell phone. Together they have a

nikklg [1K]

25+N=61.
N= 36
So there is 36 numbers in Abby's cell phone.

5 0

3 years ago

Read 2 more answers

3x + 2y = 4 4x + 3y = 7