Using whole numbers, fractions and decimals, the following equations have the sum of 10.
1. 6 + 3 + 1 = 10
2. 2.25 + 4.25 + 3.50 = 10
3. 7/2 + 5/2 + 8/2 = 10
4. 25/5 + 15/5 + 10/5 = 10
5. 6 + 2. 25 + 1.75 =10
6. 3.26 + 4. 52 + 2.22 = 10
7. 5+ 3 + 2 = 10
8. 3/4 + 4/2 =10
Answer:
hmmmm
Step-by-step explanation:
Yes. If the selection is random, it would be idetified as a random selection. This is only if the largest cities were chosen.
132 in^2
10 x 10 = 100
(1/2)(10+6)(4) = 32
100 + 32 = 132
Answer:
see below
Step-by-step explanation:
Using the segment addition postulate
AB + BC = AC
x+2 + 7x-3 = AC
Combine like terms
8x -1 = AC
Using the segment addition postulate
PQ + QR = PR
8y+5 + QR = 13y+25
Subtract 8y from each side
5 + QR = 13y-8y+25
5 + QR = 5y+25
Subtract 5 from each side
QR = 5y+25-5
QR = 5y+20
Let <em>x</em> equal the lowest of the 3 consecutive odd integers:
(x) + (x + 2) + (x + 4) = 75
Combine like terms:
3x + 6 = 75
-6 -6
3x = 69
/3 /3
<u><em>x = 23</em></u>
The lowest integer is 23. The 3 integers, therefore, are 23, 25, and 27.
Hope this helps!
<em>~ArchimedesEleven</em>
