A person pushes an object of mass 5.0 kg along the floor by applying a
1 answer:
Answer:
<em>The magnitude of the force exerted by the person is 100 N</em>
Explanation:
<u>Net Force</u>
According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:
Fn = ma
Where a is the acceleration of the object.
The net force is the sum of all forces exerted over a body. When an object is moved along a rough surface it experiences two horizontal forces and two vertical forces (provided there is no vertical component of the applied force).
The vertical forces are the Normal and the Weight and they are balanced, i.e.: N = W = mg.
The horizontal forces are The applied force (Fa) and the friction force (Fr). They are not balanced because the object is accelerated in that direction. The net force is:
Fn = Fa - Fr
Applying the first equation:
Fa - Fr = ma
Solving for Fa:
Fa = Fr + ma
Substituting the given values m=5 kg, Fr=10 N, .
Fa = 10 + 5*18 = 10 + 90 = 100
Fa = 100 N
The magnitude of the force exerted by the person is 100 N
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Answer:
The kinetic energy of the merry-goround after 3.62 s is 544J
Explanation:
Given :
Weight w = 745 N
Radius r = 1.45 m
Force = 56.3 N
To Find:
The kinetic energy of the merry-go round after 3.62 = ?
Solution:
Step 1: Finding the Mass of merry-go-round
m = 76.02 kg
Step 2: Finding the Moment of Inertia of solid cylinder
Moment of Inertia of solid cylinder I =
Substituting the values
Moment of Inertia of solid cylinder I
=>
=>
=>
Step 3: Finding the Torque applied T
Torque applied T =
Substituting the values
T =
T = 81.635 N.m
Step 4: Finding the Angular acceleration
Angular acceleration ,
Substituting the values,
Step 4: Finding the Final angular velocity
Final angular velocity ,
Substituting the values,
Now KE (100% rotational) after 3.62s is:
KE =
KE =
KE = 544J
Answer:
x = 102.33 m
Explanation:
Given that,
Position where a forest ranger stands is 35 m above the ground. The angle of depression to the base of the fire is 20. We need to find how far from the tower is the fire.
Let the distance is x. We can find x using trigonometry as follows :
Hence, the fire is at a distance of 102.33 m from the fire.
Answer:
T = 23.92 m
Explanation:
given,
mass of the diver = 50.9 Kg
Resistant force from the water = f = 1492 N
diver come top rest under water at a distance = 6 m
acceleration due to gravity = 9.81 m/s²
final velocity = v = 0 m/s
initial velocity = u = ?
total distance = ?
Now acceleration of body under water
f = m a
using equation of motion
v² = u² + 2 a s
0 = u² - 2 x 29.31 x 6
u = 18.75 m/s
now.
calculating distance of the diver in air
v² = u² + 2 a s
0 = 18.75² - 2 x 9.81 x s
s = 17.92 m
total distance
T = 17.92 + 6
T = 23.92 m
the total distance between the diving board and the diver’s stopping point underwater T = 23.92 m