All categories

3 years ago

If something changes motion, are forces balanced or unbalanced?

2 answers:

5 0

When the motion of an object changes, the forces are unbalanced. Balanced forces are equal in size and opposite in direction. ... When the forces on an object are equal and in opposite directions, the forces are balanced, and there is no change in motion.

Sholpan [36]3 years ago

3 0

Answer:

The forces are unbalanced.

Explanation:

"When the motion of an object changes, the forces are unbalanced. Balanced forces are equal in size and opposite in direction. When forces are balanced, there is no change in motion."

You might be interested in

Given a sphere with radius r, find the height of a pyramid of minimum volume whose base is a square and whose base and triangula

BaLLatris [955]

Answer:

The Height of a pyramid is 4r.

Explanation:

Explanation is in the following attachments

6 0

4 years ago

A car with a velocity of 6.4 m/s, forward, accelerates to a velocity of 10.6 m/s, forward, in 16 s. What is the card acceleratio

tatuchka [14]

Answer:

acceleration = 0.2625 m/s²

Explanation:

acceleration = ( final velocity - initial velocity ) / time

Here the final velocity is 10.6 m/s and initial velocity is 6.4 m/s and time is 16 s.

using the equation:

acceleration = ( 10.6 - 6.4 ) / 16

= 0.2625 m/s²

6 0

3 years ago

Read 2 more answers

What is the escape velocity from a planet with a mass that is 10.8% Earths mass and a size that is 53% Earths radial size?

DENIUS [597]

The escape velocity from the planet is 5052 m/s

Explanation:

The formula to calculate the escape velocity from a planet is:

$v=\sqrt{\frac{2GM}{R}}$

where

$G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}$ is the gravitational constant

M is the mass of the planet

R is the radius of the planet

For Earth,

$M_E=5.98\cdot 10^{24} kg$ is the mass

$R_E=6.37\cdot 10^6 m$ is the radius

Here we have a planet that:

- its mass is 10.8% of that of Earth, so

$M=0.108M_E$

- its radius is 53% of that of Earth, so

$R=0.53 R_E$

Substituting everything into the first equation, we find the escape velocity from this planet:

$v=\sqrt{\frac{2G(0.108M_E)}{0.53R_E}}=\sqrt{\frac{2(6.67\cdot 10^{-11})(0.108)(5.98\cdot 10^{24})}{(0.53)(6.37\cdot 10^6)}}=5052 m/s$

#LearnwithBrainly

4 0

3 years ago

An apple in a tree has a gravitational store of 8J. As it falls, it accelerates constantly until it hits the ground. What is the

Masja [62]

Answer:

Explanation:

Given that on the tree the gravitational energy stored is 8J

Then, mgh = 8J.

The apple begins to fall and hit the ground, what is the maximum kinetic energy?

Using conservation of energy, as the above is about to hit the ground, the apple is at is maximum speed, and the height then is 0m, so the potential energy at the ground is zero, so all the potential of the apple at the too of the tree is converted to kinetic energy as it is about to hits the ground. Along the way to the ground, both the Kinetic energy and potential energy is conserved, it is notice that at the top of the tree, the apple has only potential energy since velocity is zero at top, and at the bottom of the tree the apple has only kinetic energy since potential energy is zero(height=0)

So,

K.E(max) = 8J

7 0

3 years ago

A resource, such as oil, that cannot regenerate in a reasonable amount of time is called

Anna11 [10]

A resource, such as oil, that cannot regenerate in a reasonable amount of time, such as a human lifetime, is called a "nonrenewable" resource.<em> (A) </em>

Once it's gone, it's gone.

7 0

3 years ago

Read 2 more answers