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sleet_krkn [62]
4 years ago
9

Describe a process that converts chemical energy to thermal energy

Physics
1 answer:
nata0808 [166]4 years ago
5 0

Examples of such processes include:

1. Gasoline is ignited in a car engine. As the gasoline burns, it creates  small explosions which release heat or thermal energy which moves the pistons and thus the car moves forward.

2. Chemical energy in coal is released as the coal burns to release heat or thermal energy which is used to  heat water  e.g. in a power plant resulting in production of steam to turn turbines.

3. A butane torch burns gas. As the chemical bonds are broken, the thermal  energy released increases the heat energy of a metal which melts and  thus two pieces of a metal can be welded together.

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Answer:

brightness that we observe from a star is related to the energy produced and the distance to the Earth

Explanation:

In stars, the color that we observe is directly related to the temperature of the star by the y of the Wien displacement.

             λ_{max} T = 2,898 10³

the brightness that we observe from a star is related to the energy produced and the distance to the Earth

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3 years ago
What is the relationship between electricity and magnetism? A. A moving magnet creates a current, and a still magnet creates a c
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I'm trusting my gut and saying it's B.
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Twenty- four specific objects transmit complex radio codes, including time signals traveling at the speed of light. You can cont
Mademuasel [1]

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GPS Satellites.

Explanation:

You will always be able to have access to 4 of them no matter where you are on the Earth. This is useful for triangulation.

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3 years ago
If you divide velocity by time what unit do you get
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m/s^2, acceleration

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4 0
3 years ago
Read 2 more answers
A ball is hit 1 meter above the ground with an initial speed of 40 m/s. If the ball is hit at an angle of 30 above the horizonta
Vika [28.1K]

Answer:

t_t=4.131\ s

Explanation:

Given:

height above the horizontal form where the ball is hit, y=1\ m

angle of projectile above the horizontal, \theta=30^{\circ}

initial speed of the projectile, u=40\ m.s^{-1}

<u>Firstly we find the </u><u>vertical component of the initial velocity</u><u>:</u>

u_y=u.\sin\theta

u_y=40\times \sin30^{\circ}

u_y=20\ m.s^{-1}

During the course of ascend in height of the ball when it reaches the maximum height then its vertical component of the velocity becomes zero.

So final vertical velocity during the course of ascend:

  • v_y=0\ m.s^{-1}

Using eq. of motion:

v_y^2=u_y^2-2g.h (-ve sign means that the direction of velocity is opposite to the direction of acceleration)

0^2=20^2-2\times 9.8\times h

h=20.4082\ m (from the height where it is thrown)

<u>Now we find the time taken to ascend to this height:</u>

v_y=u_y-g.t

0=20-9.8t

t=2.041\ s

<u>Time taken to descent the total height:</u>

  • we've total height, h'=h+y =20.4082+1

h'=u_y'.t'+\frac{1}{2} g.t'^2

  • during the course of descend its initial vertical velocity is zero because it is at the top height, so u_y'=0\ m.s^{-1}

21.4082=0+4.9t'^2

t'=2.09\ s

<u>Now the total time taken by the ball to hit the ground:</u>

t_t=t'+t

t_t=2.09+2.041

t_t=4.131\ s

3 0
3 years ago
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