The point-slope form of the equation for a line can be written as
... y = m(x -h) +k . . . . . . . for a line with slope m through point (h, k)
Your function gives
... f'(h) = m
... f(h) = k
a) The tangent line is then
... y = 5(x -2) +3
b) The normal line will have a slope that is the negative reciprocal of that of the tangent line.
... y = (-1/5)(x -2) +3
_____
You asked for "an equation." That's what is provided above. Each can be rearranged to whatever form you like.
In standard form, the tangent line's equation is 5x -y = 7. The normal line's equation is x +5y = 17.
9514 1404 393
Answer:
448
Step-by-step explanation:
(4 pt/da)×(7 da/wk)×(16 oz/pt) = 448 oz/wk
That would be 448 fluid ounces per week.
Answer:
y=-|x+1|+1
Step-by-step explanation:
It's an absolute value function vertically flipped and shifted 1 unit to the left, 1 unit to the the top.
Answer:
let me think
Step-by-step explanation:
i want free points
I think it would have crystal formations if I remember correctly.
