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aalyn [17]
3 years ago
5

2. A satellite can generate a maximum force of 550 N using its rockets. The

Chemistry
1 answer:
Gemiola [76]3 years ago
6 0

The satellite's rockets fire in 18.54 s

<h3>Further explanation</h3>

Given

F- Force = 550 N

I - impulse = 10,200 kg m/s

Required

Fire time

Solution

Impulse is defined is the product of the force with the time interval when the force is acting on the object.  

Can be formulated :

I = F. Δt  

Δt  = I : F

Input the value :

\tt \Delta t=\dfrac{I}{F}\\\\\Delta t=\dfrac{10200}{550}\\\\\Delta t=\boxed{\bold{18.54~s}}

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5

Explanation:

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3 years ago
What substance is oxidized in the following reaction? 4HCl + MnO2 → Cl2 + 2H2O + MnCl2
Blizzard [7]

Answer:

Cl⁻ was oxidized.

Explanation:

  • 4HCl + MnO₂ → Cl₂ + 2H₂O + MnCl₂

Oxidation can be defined as the process in which the oxidation number of a substance increases.

On the left side of the equation, Cl has a charge of -1 (in HCl); while on the right side of the equation Cl has a charge of 0 in Cl₂.

Thus, Cl⁻ was oxidized.

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Which conclusion is supported by the information in the graph?
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A. The cost of producing a kilowatt of power with fuel cell will be less than $30 in 2015

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2 years ago
When 9.2 g of frozen N2O4 is added to a 0.50 L reaction vessel and the vessel is heated to 400 K and allowed to come to equilibr
Amanda [17]

<u>Answer:</u> The value of K_c for the given reaction is 1.435

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}

Given mass of N_2O_4 = 9.2 g

Molar mass of N_2O_4 = 92 g/mol

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Putting values in above equation, we get:

\text{Molarity of solution}=\frac{9.2g}{92g/mol\times 0.50L}\\\\\text{Molarity of solution}=0.20M

For the given chemical equation:

                 N_2O_4(g)\rightleftharpoons 2NO_2(g)

<u>Initial:</u>          0.20

<u>At eqllm:</u>     0.20-x        2x

We are given:

Equilibrium concentration of N_2O_4 = 0.057

Evaluating the value of 'x'

\Rightarrow (0.20-x)=0.057\\\\\Rightarrow x=0.143

The expression of K_c for above equation follows:

K_c=\frac{[NO_2]^2}{[N_2O_4]}

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[N_2O_4]_{eq}=0.057M

Putting values in above expression, we get:

K_c=\frac{(0.286)^2}{0.143}\\\\K_c=1.435

Hence, the value of K_c for the given reaction is 1.435

6 0
3 years ago
2. What is the mass of 16.3 L of helium gas?
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(16.3 L) / (22.414 L/mol) x (4.0026 g He/mol) = 2.91 g

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