Answer: B
Explanation:
Let us first resolve the forces.
Horizontal, the vectorial resolution is equal to zero. Since the positive direction and negative direction vector are of same magnitude. Therefore, summation of horizontal forces Fh = 0
Vertical resolution, the sum of forces will be Fv = 30 - 35 = - 5 N
Resultant force F = sqrt( Fv^2 + Fh^2)
Substitutes Fv and Fh. We get
R = sqrt ( 25) = 5N
We are given that the mass M = 2kg
From Newton second law,
F = Ma
Where a = acceleration
Substitute F and M and make a the subject of formula
5 = 2a
a = 5/2 = 2.5 m/s^2
Therefore, acceleration a of the object is 2.5 m/s^2 down.
Incomplete question.The complete question is
A tall cylinder contains 20 cm of water. Oil is carefully poured into the cylinder, where it floats on top of the water, until the total liquid depth is 40 cm. What is the gauge pressure at the bottom of the cylinder? Suppose that the density of oil is 900 kg/m3.
Answer:
Total gauge pressure= 3724Pa or 3.724kPa
Explanation:
Pressure (water alone) = (1,000 x 9.8 x 0.2m) = 1,960Pa.
Pressure (oil on top) = (900 x9.8 x 0.2m) = 1,764Pa.
Total gauge pressure at bottom = (1,960 + 1,764) = 3724Pa or 3.724kPa
Answer
given,
radius of earth = 6370 km
earths latitude = 55° N
time = 24 hour = 86400 s
angular speed = ω
a) 
b) 
c) ω at equator
d)
Current = Power/Voltage = 60/120 = 0.5 amperes
Yes, because a crumpled piece of paper has more center mass, allowing it to fall faster.
