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maks197457 [2]
3 years ago
13

What waves have wavelengths longer than those of visible light? Give an example of how each kind of wave is used.

Physics
1 answer:
egoroff_w [7]3 years ago
7 0
<span>The visible light has wavelength in the range 400 - 700 nano-meters. The wavelengths longer than visible light are: 1-Infrared waves (used in ringtone/mobile waves)2-microwaves - used to heat and cook food. 3- Radio waves - used in communication purposes.</span>
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A cube of side 6.50 cm is placed in a uniform field E = 7.50 × 10^3 N/C with edges parallel to the field lines (field enters the
Svetllana [295]

Answer:

a) \Phi_{net} = 0\,\frac{N\cdot m^{2}}{C}, b) \Phi_{right} = -31.688\,\frac{N\cdot m^{2}}{C}, c) \Phi_{left} = 31.688\,\frac{N\cdot m^{2}}{C}

Explanation:

a) The net flux through the cube is:

\Phi_{net}=-(7.50\cdot 10^{3}\,\frac{N}{C} )\cdot (0.065\,m)^{2}+(7.50\cdot 10^{3}\,\frac{N}{C} )\cdot (0.065\,m)^{2}

\Phi_{net} = 0\,\frac{N\cdot m^{2}}{C}

b) The flux through the right face is:

\Phi_{right}=-(7.50\cdot 10^{3}\,\frac{N}{C} )\cdot (0.065\,m)^{2}

\Phi_{right} = -31.688\,\frac{N\cdot m^{2}}{C}

c) The flux through the left face is:

\Phi_{left}=(7.50\cdot 10^{3}\,\frac{N}{C} )\cdot (0.065\,m)^{2}

\Phi_{left} = 31.688\,\frac{N\cdot m^{2}}{C}

5 0
3 years ago
Read 2 more answers
What does attributed mean
Dmitriy789 [7]

Answer:

attribute is defined as a quality or characteristic of a person, place, or thing

Explanation:

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a boy throw a ball upward from the top of a cliff 73m high.Calculate the time in which ball will fall on the ground and the velo
LekaFEV [45]

The ball rises for v/g seconds; which equals 14.7/9.8=1.5 seconds . After this time, it’s height will be:


h(t)=g/2(1.5)²+14.7(1.5)


=-4.9 x 2.25 + 22.05


=11.025m


The ball then falls for 49+11.025=60.025m, which takes:


g/2t²=60.025


t²=12.25


t=3.5 secs


Total time: 1.5+3.5=5 seconds

3 0
3 years ago
What is the minimum frequency with which a 200-turn, flat coil of cross sectional area 300 cm2 can be rotated in a uniform 30-mT
sergiy2304 [10]

Answer:

The minimum frequency of the coil is 7.1 Hz

Explanation:

Given;

number of turns, N = 200 turns

cross sectional area, A = 300 cm² = 300 x 10⁻⁴ m²

magnitude of magnetic field strength, B = 30 x 10⁻³ T

maximum value of the induced emf, E = 8 V

Maximum induced emf is given as;

E = NBAω

where

ω is angular velocity (ω = 2πf)

E = NBA2πf

where;

f is the minimum frequency, measured in hertz (Hz)

f = E / (NBA2π)

f = 8 / (200 x 30 x 10⁻³  x 300 x 10⁻⁴ x 2 x 3.142)

f = 7.073 Hz

f = 7.1 Hz

Therefore, the minimum frequency of the coil is 7.1 Hz

8 0
3 years ago
When aluminum foil is formed into a loose ball, it can float on water. But when the ball of foil is pounded flat with a hammer,
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Air caught in the ball of foil makes the ball less dense than water
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