Work= force*distance
Work= x*12
Force= mass*acceleration
Force= 5 kg*6
Force= 40 N
Work= 40×12
Work= 480 J (joules)
I think this is it
Answer:
The answer is 10Nm
Explanation: I ended up just messing around with the numbers, I multiplied 5 and 2 got 10 as my answer and it was right.
x = V<em>x</em> * t
given V<em>x</em> = 10m/s n t = 3.53s
x = 10 * 3.53
= 35.3m
Answer:
The motion is over-damped when λ^2 - w^2 > 0 or when
> 0.86
The motion is critically when λ^2 - w^2 = 0 or when
= 0.86
The motion is under-damped when λ^2 - w^2 < 0 or when
< 0.86
Explanation:
Using the newton second law
k is the spring constante
b positive damping constant
m mass attached
x(t) is the displacement from the equilibrium position

Converting units of weights in units of mass (equation of motion)

From hook's law we can calculate the spring constant k

If we put m and k into the DE, we get

Denoting the constants
2λ =
= 
λ = b/0.215

λ^2 - w^2 = 
This way,
The motion is over-damped when λ^2 - w^2 > 0 or when
> 0.86
The motion is critically when λ^2 - w^2 = 0 or when
= 0.86
The motion is under-damped when λ^2 - w^2 < 0 or when
< 0.86
Answer:
it is the judicious use of energy to prevent wastage