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Aleksandr-060686 [28]
3 years ago
10

Ok, so I've answered this question but I really need someone to just check through it because I have this feeling that I've done

it wron

Physics
2 answers:
bonufazy [111]3 years ago
5 0
Your fill-ins for the first three lines of the table are correct.  Good work.

You have all the same answers for the last 2 lines of the table, like
it makes no difference to anything whether S2 is open or closed. 
That's not correct. It does make a difference.  If S2 is closed, then
the current would much rather go through S2 than through the bulbs
C and D because it's so much easier, and that's exactly what it does.
When S2 is closed, bulbs C and D are off. 

But I'll say again:  Except for those two middle boxes on the bottom line
of the table, everything else is correct.  That's 12 correct fill-ins for you,
and only 2 incorrect ones.  That's a score of 86% !  After posting so many
of these on Brainly this afternoon, doesn't it feel great to do your own work
for a change, and get it almost all correct ?
olga_2 [115]3 years ago
4 0
I believe you are correct
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A girl at an airport rolls a ball north on a moving walking that moves east. If the ball’s speed with respect to the walkway is
sweet-ann [11.9K]

We have to add two vectors.

Vector #1: 0.15 m/s north

Vector #2: 1.50 m/s east

Their sum:

Magnitude: √(0.15² + 1.50²)

Magnitude = √(0.0225+2.25)

Magnitude = √2.2725

Magnitude = <em>1.5075 m/s</em>

Direction = arctan(0.15/1.50) north of east

Direction = <em>5.71° north of east</em>

4 0
3 years ago
A 270,000 kg rocket in gravity -free space expels 270 kg of fuel by exerting a force of 360 N on it. Find the magnitude of the a
Brut [27]
F = m a 
360 = 270 x a
1.3 = a
4 0
3 years ago
A car travels along a clear 10.0 km section of motorway in 6.0 minutes. It then drives through 3.0 km of roadwork in 3.0 minutes
Charra [1.4K]
  • 6min=1/10h=0.1h
  • 3min=1/20h=0.05h

\\ \bull\tt\dashrightarrow Avg\:Speed=\dfrac{Total\:Displacement}{Total\:Time}

\\ \bull\tt\dashrightarrow Avg\:Speed=\dfrac{10+3}{0.1+0.05}

\\ \bull\tt\dashrightarrow Avg\:Speed=\dfrac{13}{0.15}

\\ \bull\tt\dashrightarrow Avg\:Speed=86.6km/h

5 0
2 years ago
ear the end of a marathon race, the first two runners are separated by a distance of 45.0 m. The front runner has a velocity of
sesenic [268]

Answer:

a) V_{2/1}=0.8m/s

b) The second runner will win

c) d = 10.54m

Explanation:

For part (a):

V_{2/1} = V_{2} - V_{1} = 0.8m/s

For part (b) we will calculate the amount of time that takes both runners to cross the finish line:

t_{1} = \frac{X_{1}}{V_{1}}=\frac{250}{3.45}=72.46s

t_{2} = \frac{X_{2}}{V_{2}}=\frac{250+45}{4.25}=69.41s

Since it takes less time to the second runner to cross the finish line, we can say the she won the race.

For part (c), we know how much time it takes the second runner to win, so we just need the position of the first runner in that moment:

X1 = V1*t2 = 239.46m  Since the finish line was 250m away:

d = 250m - 239.46m = 10.54m

6 0
3 years ago
Read 2 more answers
What is the most abundant gas in the atmosphere?
Snowcat [4.5K]

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8 0
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