<h3>
Answer: 21.4 square meters</h3>
Work Shown:
A = area of the front triangular face
A = base*height/2
A = 2*1.7/2
A = 1.7
L = lateral area
L = (perimeter of the base)*(depth)
L = (2+2+2)*(3)
L = 18
SA = total surface area of a triangular prism
SA = 2*A+L
SA = 2*1.7+18
SA = 21.4 square meters
Answer:
4^x+1
Step-by-step explanation:
because i got it wrong
We have,
t = 6.21 s
s = 111 m
u = 0 m/s
To determine: "a" of the particle.
We know,
s = ut + ½ at²
⇒ s = ½ at²
⇒ a = 2s/t²
⇒ a = [2(111 m)]/(6.21 s)²
⇒ a = (222 m)/(38.5641 s²)
⇒ a ≈ 5.75 m/s²
Answer:
? = 55
Step-by-step explanation:
if we put the triangles onto of each other
side CT is on top of TR
126 ÷ 70 = 1.8
70 × 1.8 = 126
BT is on top of TS
so,
99 ÷ ? = 1.8
99 = 1.8 × ?
99 ÷ 1.8 = ?
55 = ?
55 × 1.8 = 99
Hoped i helped :)
