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kow [346]
3 years ago
12

A speaker is designed for wide dispersion for a high frequency sound. What should the diameter of the circular opening be in a s

peaker where the desired diffraction angle is 75° and a 9100 Hz sound is generated? The speed of sound is 343 m/s
Physics
1 answer:
Greeley [361]3 years ago
6 0

Answer:

a = 4.76 cm

Explanation:

As we know by the law of diffraction through circular aperture

a sin\theta = 1.22 \lambda

here we know that

a = diameter of the aperture

\theta = diffraction angle

\lambda = wavelength

now we have

a = \frac{1.22 \lambda}{sin\theta}

Now in order to find the wavelength we know

\lambda = \frac{c}{f}

\lambda = \frac{343}{9100}

\lambda = 0.0376 m

now we have

a = \frac{1.22(0.0376)}{sin75}

a = \frac{0.046}{0.966}

a = 0.0476 m= 4.76 cm

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