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kow [346]
3 years ago
12

A speaker is designed for wide dispersion for a high frequency sound. What should the diameter of the circular opening be in a s

peaker where the desired diffraction angle is 75° and a 9100 Hz sound is generated? The speed of sound is 343 m/s
Physics
1 answer:
Greeley [361]3 years ago
6 0

Answer:

a = 4.76 cm

Explanation:

As we know by the law of diffraction through circular aperture

a sin\theta = 1.22 \lambda

here we know that

a = diameter of the aperture

\theta = diffraction angle

\lambda = wavelength

now we have

a = \frac{1.22 \lambda}{sin\theta}

Now in order to find the wavelength we know

\lambda = \frac{c}{f}

\lambda = \frac{343}{9100}

\lambda = 0.0376 m

now we have

a = \frac{1.22(0.0376)}{sin75}

a = \frac{0.046}{0.966}

a = 0.0476 m= 4.76 cm

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Rewire each of the following using the correct prefix using 2 decimal places where applicable.
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3 years ago
An office heater puts out 2050 btus of energy in the form of heat per hour. given that 1 btus =1.055 kj, how many megajoules of
ivolga24 [154]
<span>Assuming continuous operation (24/7), we can say that

Energy produced : Energy per hour * 24 (number of hours in a day) - 365 (number of days in a year.

Energy per hour: 2050 * 1.055 = 2162.75 kg.

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E: 2162.75 * 24 * 365 = 18,945,690 kj per year.

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4 0
3 years ago
The Acorn Insurance Company charges $3.50 for each unit of coverage under a block of 1-year term life insurance policies. The an
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$175

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8 0
3 years ago
10. A book has a mass of 400 g. The surface of the book in contact with a table has dimensions 0.10m x 0.20 m. The gravitational
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The pressure exerted on the table due to the book is 200 N/m².

The given parameters;

  • <em>mass of the book, m = 400 g = 0.4 kg</em>
  • <em>dimension of the table,  = 0.10m x 0.20 m.</em>
  • <em>gravitational field strength g =  10 N/kg.</em>

The area of the table is calculated as follows;

A = 0.1 x 0.2 = 0.02 m²

The pressure exerted on the table due to the book is calculated as follows;

P = \frac{F}{A}

where;

  • <em>F is the force of the book due to its weight</em>

<em />

P =\frac{F}{A} = \frac{mg}{A} = \frac{0.4 \times 10}{0.02} = 200 \ N/m^2

Thus, the pressure exerted on the table due to the book is 200 N/m².

Learn more here:brainly.com/question/21935783

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3 years ago
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