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VARVARA [1.3K]
3 years ago
6

Is the text in red correct (0n0')

Physics
1 answer:
Ede4ka [16]3 years ago
8 0
Yes the text in the red is correct.
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Planet Kling has half the radius and 2 times the mass of the Earth. What is the best estimate for the magnitude of the gravitati
Vlad [161]

Answer:80 m/s^2

Explanation:

6 0
3 years ago
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What are the periodic variations in Earth's rotation and orbit around the sun that alter the way solar radiation is distributed
Dahasolnce [82]

Answer:

1. The precession of the equinoxes.

2. Changes in the tilt angle of Earth’s rotational axis relative to the plane of Earth’s orbit around the Sun.

3. Variations in the eccentricity

Explanation:

These variations listed above;  the precession of the equinoxes (refers, changes in the timing of the seasons of summer and winter), this occurs on  a roughly about 26,000-year interval; changes in the tilt angle of Earth’s rotational axis relative to the plane of Earth’s orbit around the Sun, this occurs roughly in a 41,000-year interval; and changes in the eccentricity (that is a departure from a perfect circle) of Earth’s orbit around the Sun, occurring on a roughly 100,000-year timescale. which influences the mean annual solar radiation at the top of Earth’s atmosphere.

5 0
3 years ago
How does Earth's surface and the structures on the surface change as a result of an earthquake? Help me pls and I will give Brai
EastWind [94]
<span>Earthquakes often cause dramatic changes at Earth's surface. In addition to the ground movements, other surface effects include changes in the flow of groundwater, landslides, and mudflows. Earthquakes can do significant damage to buildings, bridges, pipelines, railways, embankments, dams, and other <span>structures</span></span>
6 0
4 years ago
What is one measurement needed to calculate the speed of an object? Direction Mass Time Velocity
Vlad [161]

The answer is Time.

Formula: Distance/Time

3 0
3 years ago
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A student was asked to push a large box down the hallway about 35 meters. the task took the student five minutes and a force of
zaharov [31]
Rate of work or Power done by the student can be computed with below formulas.
1. Formula for Work
Work = Force x distance
Force or F = Force applied to the object 
distance or d = displacement

2. Formula for Power
P = Work done / Time it was done or completed

Substituting the values we have,
Work or Work done = 150 N x 35 meters = 5250 J (unit of work).

Lastly computing for the rate we have,
Power or rate of work = 5250 J / 300 seconds (or 5 min) = 17.5 Joule/S or Watts

Answer is 17.5 watts

5 0
3 years ago
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