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Fudgin [204]
2 years ago
9

A roller coaster car of mass m = 300 kg is released from rest at the top of a 60 m high hill (position A), and rolls with a negl

igible friction down the hill, through a circular loop of radius 20 m (Positions B,C,and D) and along a horizontal track
Physics
1 answer:
Triss [41]2 years ago
7 0

Answer:

The principle of conservation of energy and angular momentum

Explanation:

At point A, the car experienced maximum of potential energy

As it moves down the hill, the potential energy decreases while the kinetic energy increases.

The maximum kinetic energy of the car is needed for the attainment of enough centripetal force to help the car move through the loop without falling .

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What is the shape of the trajectory that a charged particle follows in a uniform magnetic field?
Darya [45]

Answer:

circle

Explanation:

5 0
3 years ago
If the 50 kg boy were in a spacecraft 5.0r from the center of the earth, what would his weight be?
Lady_Fox [76]
·The acceleration of gravity is proportional to

                       1 / (the square of the distance from the center) .

When we're on the surface, we're 1 radius from the center of the Earth,
and the acceleration of gravity is  9.8 m/s² .

The boy's weight = (mass) · (gravity) = (50kg) · (9.8 m/s²)

                                                             =      490 newtons .

At the distance of 5 radii from the center (4 radii altitude from the surface),
the acceleration of gravity is

                 (9.8 m/s²) · (1/5)²  =  0.39 m/s² .

The boy's weight is    (mass) · (gravity)  =  (50kg) · (0.39 m/s²)

                                                                  =     19.6 newtons .

Just as we expected, his weight at that distance is

         (19.6 / 490) = 0.04  =  1/25  =  1/5²  of his weight on the surface.
7 0
2 years ago
HELP PLS LIKE RIGHT NOW PLSSSSSS
Anit [1.1K]
The answer is A for this one
5 0
2 years ago
if you stand on one side of a strike-slip fault and the block on the other side of the fault has moved to your left, this is kno
katrin [286]

If you stand on one side of a strike-slip fault and the block on the other side of the fault has moved to your left, this is known as a(n)  left lateral fault.

There are several distinct sorts of fault lines, and they are called based on the fault's movement and the fault plane's own direction. These faults may be found all over the world, but the most active and earthquake-producing ones are in the Pacific Ocean's Ring of Fire region.

When you gaze along the length of a fault line, the left side will move toward you while the right side moves away from you. This is referred to as a left-lateral fault.

To know more about   left lateral fault visit : brainly.com/question/14136640

#SPJ4

3 0
1 year ago
Light travels at 3. 0 × 108 m/s in a vacuum and slows to 2. 0 × 108 m/s in glass. What is the index of refraction of glass?.
Sergio039 [100]

The required value of the index of refraction of glass is 1.5.

Given data:

The speed of light in a vacuum is, c = 3.0 \times 10^{8} \;\rm m/s.

The speed of light in a glass is, v = 2.0 \times 10^{8} \;\rm m/s.

Light has the tendency to travel from one medium to another, then the difference between the speeds of light in various mediums is determined by a term, known as the index of refraction. The mathematical expression for the index of refraction of glass is,

n = c / v

Solving as

n = \dfrac{3.0 \times 10^{8}}{2.0 \times 10^{8}}\\\\n = 1.5

Thus, we can conclude that the required value of the index of refraction of glass is 1.5.

Learn more about the index of refraction here:

brainly.com/question/17156275

5 0
2 years ago
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