Answer- 10
Expiration-
425/100 x 10 = 42.5
Which ever expression is 3x + 21 + 10 ..... 21 + 10 = 31 .... So it'll be 3x + 31 .
Answer:
you don't know how to take proper pics..
you looks a little boring..
and maybe intelligent..
and can't tell more since it's not very clear
F(z) = 2z - (3+i)
1) second interate for z0 = i
first iterate = f(z0) = f(i) = 2i - 3 - i = i - 3 = z1
second iterate = f(z1) = f(i-3) = 2(i-3) - 3 - i = 2i - 6 - 3 - i = i - 9
2) third iterate for z0= 3 - i
first iterate = f(z0) = f(3 - i) = 2(3-i) - (3+i) = 6 -2i -3 - i =3 - 3i = z1
second iterate = f(z1) = f(3 -3i) = 2(3-3i) - (3+i) = 6 - 6i -3 -i = 3 - 7i = z2
third iterate = f(z2) = f(3 - 7i) = 2 (3-7i) - (3+i) = 6 - 14i - 3 - i = 3 -15i = z3.
3) first iterate for z0=0.5+i
first iterate = f(z0) = f(0.5 +i) = 2(0.5+i) - (3+i) = 1 +2i - 3 - i = - 2 + i = z1
4) third iterate for z0=-2-5i
first iterate = f(z0) = 2(- 2 - 5i) - (3 + i) = - 4 - 10i - 3 - i = -7 - 11i = z1
second iterate = f(z1) = 2( - 7 - 11i) - (3+i) = -14 - 22i - 3 - i = -17 -23i = z2
third iterate = f(z2) = 2(-17-23i) -(3+i) = -34 - 46i -3 - i = -37 - 47i = z3
Answer:
Solutions are (3,1) and (4,2)
Step-by-step explanation:
Graph is shown in the attached sheet
Given are two systems of equations and we have to solve them using graph
For graphing let us first prepare table for x and y.
1) 
I line II line
x 0 4.5 3 x 0 2.5 3
y 3 0 1 y -5 0 1
The two lines intersect at (3,1)
Hence solution is (3,1)
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2) 
I line II line
x 0 2 4 x 0 6 4
y 0 1 2 y 3 0 2
The two lines intersect at (4,2)
Hence solution is (4,2)
