2. Determine which of the following relations is a function. (Lesson 1-7)

Mathematics

1 answer:

velikii [3]3 years ago

5 0

Answer:

Step-by-step explanation:

H is the answer because in the simplest and easy way I can explain this is that it does have the same x in the table. If you look at F the x 0 repeats twice in the third and forth point. If you look at G the x -3 repeats twice in the first and second point. If you look at J the x 2 repeats twice in the first and forth point. The only answer choice does repeats any of the x's is H with the x's of -4, -2, -1, and 3. So with this being said H is the answer.

The y can repeat as a function just not the x.

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For a binomial distribution with p = 0.20 and n = 100, what is the probability of obtaining a score less than or equal to x = 12

notsponge [240]

The binomial distribution is given by,
P(X=x) = $(^{n}C_{x})p^{x} q^{n-x}$
q = probability of failure = 1-0.2 = 0.8
n = 100
They have asked to find the probability of obtaining a score less than or equal to 12.
∴ P(X≤12) = $(^{100}C_{x})(0.2)^{x} (0.8)^{100-x}$
where, x = 0,1,2,3,4,5,6,7,8,9,10,11,12
∴ P(X≤12) = $(^{100}C_{0})(0.2)^{0} (0.8)^{100-0} + (^{100}C_{1})(0.2)^{1} (0.8)^{100-1}$ + $(^{100}C_{2})(0.2)^{2} (0.8)^{100-2} + (^{100}C_{3})(0.2)^{3} (0.8)^{100-3}$ + $(^{100}C_{4})(0.2)^{4} (0.8)^{100-4} + (^{100}C_{5})(0.2)^{5} (0.8)^{100-5}$ + $(^{100}C_{6})(0.2)^{6} (0.8)^{100-6} + (^{100}C_{7})(0.2)^{7} (0.8)^{100-7}$ + $(^{100}C_{8})(0.2)^{8} (0.8)^{100-8} + (^{100}C_{9})(0.2)^{9} (0.8)^{100-9}$ + $(^{100}C_{10})(0.2)^{10} (0.8)^{100-10} + (^{100}C_{11})(0.2)^{11} (0.8)^{100-11}$ + $(^{100}C_{12})(0.2)^{12} (0.8)^{100-12}$

Evaluating each term and adding them you will get,
P(X≤12) = 0.02532833572
This is the required probability.

7 0

4 years ago

Subtract. 5x – 6x+2 - 1-2x - x - 2)

adell [148]

Answer:

7x^2 -5x + 4

Step-by-step explanation:

5x^2 – 6x+2

- (-2x^2 - x - 2)

We got 5x^2 - (-2x^2) = 5x^2 + 2x^2 = 7x^2

-6x - (-x) = -6x + x = -5x

2 - (-2) = 2+2 = 4