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3 years ago

The chemical formula for the compound strontium sulfide, which contains Sr2+ and S2– ions, is

Chemistry

1 answer:

Slav-nsk [51]3 years ago

3 0

The chemical formula for the compound strontium sulphide would be SrS.

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What is the empirical formula of a compound containing carbon, hydrogen, and oxygen in the ratio 14:42:84? C14H42O84

kati45 [8]

C:H:O = 14:42:84 = 7:21:42 = 1:3:6

CH₃O₆

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3 years ago

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A gas has an initial volume of 455 mL at 105ºC and a final volume of 235 mL. What is its final temperature in Celsius degrees?

Oksana_A [137]

Hello!

To solve this problem we're going to use the Charles' Law. This Law describes the relationship between Volume and Temperature in an ideal gas. Applying this law we have the following equation:

$\frac{V1}{T1} = \frac{V2}{T2} \\ \\ T2= \frac{V2*T1}{V1}= \frac{235 mL * 105 ^{\circ}C }{455 mL}=54,23 ^{\circ}C$

So, the final temperature is 54,23 °C

Have a nice day!

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3 years ago

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What is the concentration of each type of monosaccharide in lactose

polet [3.4K]

Answer:

Lactose comprises the monosaccharides glucose and galactose and maltose, comprising two glucose molecules, which occurs in barley, wheat, and malt.

Explanation:

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2 years ago

What order do these go in? please help

pochemuha

Answer:

Chemical energy found in the bonds between atoms

Nuclear energy found in nucleus of an atom

Electrical energy found in the flow of electrical charges

Thermal energy found when internal energy is transferred.

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2 years ago

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If 1. 3618 moles of AsF3 are allowed to react with 1. 0000 mole of C2Cl6, what would be the theoretical yield of AsCl3, in moles

VARVARA [1.3K]

Answer:

AsF3:C2CI6

4:3

1.3618 moles: 1.02135 moles(1.3618÷4×3)

C2CI6 is the limting reagent

So the number of moles for AsCI3 is 0.817 moles( number of moles of the limting reagant) ÷3 ×4 (according to ratio by balancing chemical equation)=1.09 moles(3 s.f.)

Balanced equation

4AsF3 + 3C2Cl6 → 4AsCl3 + 3C2Cl2F4

Use stoichiometry to calculate the moles of AsCl3 that can be produced by each reactant.

Multiply the moles of each reactant by the mole ratio between it and AsCl3 in the balanced equation, so that the moles of the reactant cancel, leaving moles of AsCl3.

Explanation:

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2 years ago