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worty [1.4K]
3 years ago
9

What is the correct representation for the subshell with n = 2 and l = 1?

Chemistry
2 answers:
Sliva [168]3 years ago
4 0
Hey there! Hello!

When I was doing this part of chemistry, I found it easiest to do these problems with a chart. I've attached a picture of one that I printed out with some writing on it; I really wish I could find the actual picture I printed out, but I have so much on my computer and I know you need help ASAP. 

So, first thing to keep in mind is what n and l mean. "n" is the principal quantum number/level, which basically means it's the top energy level. Then, one down from that is "l," which is the angular quantum number, or the sublevel. You can refer to these however you like. Keep in mind how the number that "l" is translates to the different letters that represent sublevels:

0=s sublevel, 1=p sublevel, 2=d sublevel, and 3=f sublevel. 

<span>What the problem is asking you to do is define the subshell that has an "n" of 2 and an "l" of 1. Given what I've previously stated, the proper representation will be "2p," since your "l" value is equal to 2, or p. 

I hope that my answer (and attachment) help you out! Feel free to ask me any additional questions if you have any. :-)</span>

Alex3 years ago
3 0

Answer:

2p

Explanation: i just answered this question and it was right

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A mixture of0.161 moles of C is reacted with 0.117 moles of O2 in a sealed, 10.0 L-vessel at 500.0 K, producing a mixture of CO
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Answer:

number of moles of CO2 is 0.054

number of moles of CO is 0.107

number of moles of O2 remaining is 0.01 mole

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Explanation:

Firstly, we write the equation of reaction;

3C(s) +2O2(g) → CO2(g) +2CO(g)

Now, we proceed.

From the written equation, we can deduce that

3 mol C = 2 mol O2 = 1 mol CO2 = 2 mol CO

No of mol of C reacted = 0.161 mol

limiting reactant according to the question is Carbon

a. no of mol of CO2 formed = 0.161*1/3 = 0.054 moles ( no of moles of CO2 formed is one-third of no of moles of carbon reacted. This is obtainable from their mole ratio 1:3)

b. no of mol of CO formed = 0.161*2/3 = 0.107 mol

c. no of mol of O2 remaining = 0.117 - (0.151*2/3) = 0.117-0.107 = 0.01 mole

d. mole fraction of CO = no of mol of CO/Total number of moles

= 0.107/(0.107+0.054+0.01)

= 0.625730994152 which is approximately 0.63

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