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worty [1.4K]
3 years ago
9

What is the correct representation for the subshell with n = 2 and l = 1?

Chemistry
2 answers:
Sliva [168]3 years ago
4 0
Hey there! Hello!

When I was doing this part of chemistry, I found it easiest to do these problems with a chart. I've attached a picture of one that I printed out with some writing on it; I really wish I could find the actual picture I printed out, but I have so much on my computer and I know you need help ASAP. 

So, first thing to keep in mind is what n and l mean. "n" is the principal quantum number/level, which basically means it's the top energy level. Then, one down from that is "l," which is the angular quantum number, or the sublevel. You can refer to these however you like. Keep in mind how the number that "l" is translates to the different letters that represent sublevels:

0=s sublevel, 1=p sublevel, 2=d sublevel, and 3=f sublevel. 

<span>What the problem is asking you to do is define the subshell that has an "n" of 2 and an "l" of 1. Given what I've previously stated, the proper representation will be "2p," since your "l" value is equal to 2, or p. 

I hope that my answer (and attachment) help you out! Feel free to ask me any additional questions if you have any. :-)</span>

Alex3 years ago
3 0

Answer:

2p

Explanation: i just answered this question and it was right

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4 0
3 years ago
Using this balanced equation: 2 NaOH + H2SO4 —&gt; H2O + Na2SO4
mars1129 [50]
<h3>Answer:</h3>

266.325 g

<h3>Explanation:</h3>

We are given the balanced equation;

2NaOH + H₂SO₄ → H₂O + Na₂SO₄

  • Mass of NaOH as 150 g

We are required to determine the mass of Na₂SO₄ that will be formed.

<h3>Step 1: Determine the number of moles of NaOH</h3>

Moles = Mass ÷ molar mass

Molar mass of NaOH is 40.0 g/mol

Therefore;

Moles of NaOH = 150 g ÷ 40 g/mol

                          = 3.75 moles

<h3>Step 2: Determine the number of moles of sodium sulfate formed</h3>
  • From the equation 2 moles of NaOH reacts with sulfuric acid to form 1 mole of sodium sulfate.
  • Therefore; mole ratio of NaOH : Na₂SO₄ is 2 : 1

Thus, moles of Na₂SO₄ = Moles of NaOH ÷ 2

                                      = 3.75 moles ÷ 2

                                     = 1.875 moles

<h3>Step 3: Determine the mass of Na₂SO₄ produced.</h3>

we know that;

Mass = Moles × Molar mass

Molar mass of Na₂SO₄ is 142.04 g/mol

Therefore;

Mass of Na₂SO₄ = 1.875 moles × 142.04 g/mol

                           = 266.325 g

Thus, the mass of sodium sulfate formed 266.325 g

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3 years ago
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2 years ago
What volume of a 0.33-M C12H22O11 solution can be diluted to prepare 25 mL of a solution with a concentration of 0.025 M?
Vsevolod [243]

The dilution formula can be used to find the volume needed

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And c2 is concentration and v2 is volume of the diluted solution to be prepared

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Therefore 1.89 mL of the 0.33 M solution needs to be diluted up to 25 mL to make a 0.025 M solution

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