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konstantin123 [22]
2 years ago
5

How many molecules are in 502.1 g of NaF?

Chemistry
1 answer:
Murrr4er [49]2 years ago
7 0

Answer:

11.958129200057586 molecules

Explanation:

You might be interested in
How many grams are in 2.45E24 formula units of Fp3BZ2? The molar mass of Fp3Bz2. is 97.05<br> g/mol.
dlinn [17]

Answer:

394.99g

Explanation:

The number of moles of a substance can be calculated by dividing the number of atoms of such substance by Avagadro's number (6.02 × 10^23)

n = nA ÷ 6.02 × 10^23

The number of atoms of Fp3BZ2 in this question is 2.45E24 formula units i.e. 2.45 × 10^24

n = 2.45 × 10^24 ÷ 6.02 × 10^23

n = 2.45/6.02 × 10^(24-23)

n = 0.407 × 10¹

n = 4.07moles

Using mole = mass/molar mass

Where; molar mass of Fp3Bz2. is 97.05

g/mol.

mass = molar mass × mole

mass = 97.05 × 4.07

mass = 394.99g

4 0
2 years ago
Chemistry Help!<br> Reasons why nonmetals form covalent bonds?
melisa1 [442]
Okay thanks for reminding me
3 0
3 years ago
Read 2 more answers
Consider the reaction 2CO * O2 —&gt; 2 CO2 what is the percent yield of carbon dioxide (MW= 44g/mol) of the reaction of 10g of c
Arturiano [62]

Answer:

Y = 62.5%

Explanation:

Hello there!

In this case, for the given chemical reaction whereby carbon dioxide is produced in excess oxygen, it is firstly necessary to calculate the theoretical yield of the former throughout the reacted 10 grams of carbon monoxide:

m_{CO_2}^{theoretical}=10gCO*\frac{1molCO}{28gCO}*\frac{2molCO_2}{2molCO}  *\frac{44gCO_2}{1molCO_2}\\\\ m_{CO_2}^{theoretical}=16gCO_2

Finally, given the actual yield of the CO2-product, we can calculate the percent yield as shown below:

Y=\frac{10g}{16g} *100\%\\\\Y=62.5\%

Best regards!

8 0
2 years ago
How many valence electrons is each element trying to obtain?
lukranit [14]
An element is always trying to have 8 valence electrons. Each element must obtain a different number to come to a total of 8
3 0
3 years ago
The particles that are lost, gained, or shared in chemical reactions are
castortr0y [4]
Electrons are either lost gained or shared in chemical reactions :)
6 0
3 years ago
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