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konstantin123 [22]
3 years ago
5

How many molecules are in 502.1 g of NaF?

Chemistry
1 answer:
Murrr4er [49]3 years ago
7 0

Answer:

11.958129200057586 molecules

Explanation:

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Which is the IUPAC name for NO?
Vanyuwa [196]

Answer:

Nitrogen (ii) oxide

Explanation:

To know the IUPAC name for NO, we shall determine the oxidation number of N in NO.

NOTE: The oxidation number of oxygen (O) is always – 2.

Thus the oxidation number of N in NO can be obtained as follow:

N + O = 0 (ground state)

N + (– 2) = 0

N – 2 = 0

Collect like terms

N = 0 + 2

N = +2

Thus, the oxidation number of Nitrogen (N) in NO is +2.

Therefore, the IUPAC name for NO is Nitrogen (ii) oxide

3 0
3 years ago
Read 2 more answers
What is the scientific method describes as nonlinear
Phoenix [80]
Scientists often repeat one or more steps several times.
8 0
3 years ago
If you start with 6 moles of N2 and 6 moles of H2 (meaning you won't have enough of 1 of the ingredients), how many moles of NH3
Ivahew [28]

Answer:

4molNH_3

Explanation:

Hello there!

In this case, according to the given information it will be firstly necessary to set up the chemical equation taking place:

N_2+3H_3\rightarrow 2NH_3

We infer we need to calculate the moles of NH3 by using both of the moles of N2 and H2 at the beginning, in order to identify the limiting reactant:

n_{NH_3}=6molN_2*\frac{2molNH_3}{1molN_2}=12molNH_3\\\\ n_{NH_3}=6molH_2*\frac{2molNH_3}{3molH_2}=4molNH_3\\

Thus, since hydrogen yields the fewest moles of ammonia, we conclude that we are just able to yield 4 moles of NH3.

Regards!

8 0
3 years ago
Volume of 14.00g of nitrogen at 5.64atm and 315k
VikaD [51]

The volume of a 14.00g of nitrogen at 5.64atm and 315K is 4.59L.

<h3>How to calculate volume?</h3>

The volume of an ideal gas can be calculated using the following ideal gas equation formula;

PV = nRT

Where;

  • P = pressure (atm)
  • V = volume (L)
  • n = number of moles
  • R = gas law constant
  • T = temperature

An ideal gas is a hypothetical gas, whose molecules exhibit no interaction, and undergo elastic collision with each other and with the walls of the container.

The number of moles in 14g of nitrogen can be calculated as follows:

moles = 14g ÷ 14g/mol = 1mol

5.64 × V = 1 × 0.0821 × 315

5.64V = 25.86

V = 25.86 ÷ 5.64

V = 4.59L

Therefore, 4.59L is the volume of the gas

Learn more about volume at: brainly.com/question/12357202

#SPJ1

4 0
1 year ago
The density of a pure liquid at 25 degrees Celsius was calculated by determining the mass and volume of a sample of the liquid.
adelina 88 [10]

Answer

The density of the liquid is 0.82 g/mL.

Explanation:

From the question given above, the following data were obtained:

Mass of empty flask = 18.990 g

Mass of flask + liquid = 39.439 g

Volume of liquid = 25 mL

Density of liquid =..?

Next, we shall determine the mass of the liquid. This can be obtained as follow:

Mass of empty flask = 18.990 g

Mass of flask + liquid = 39.439 g

Mass of liquid =.?

Mass of liquid = (Mass of flask + liquid) – (Mass of empty flask)

Mass of liquid = 39.439 – 18.990

Mass of liquid = 20.503 g

Finally, we shall determine the density of the liquid as follow:

Mass of liquid = 20.503 g

Volume of liquid = 25 mL

Density of liquid =..?

Density = mass / volume

Density of liquid = 20.503 / 25

Density of liquid = 0.82 g/mL

8 0
3 years ago
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