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Vinvika [58]
2 years ago
15

PLEASE HELP ME !!!!!!

Mathematics
1 answer:
bekas [8.4K]2 years ago
8 0

Answer:fdg

Step-by-step explanation:

fdg

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GIVING BRAINLIEST! A rectangular garden has a width of 10 feet and a length of 14 feet. A cement walkway is added around the out
Serjik [45]

Given:

Width of a garden = 10 feet

Length of the garden = 14 feet

Area of the garden and the walkway together = 396 square feet.

To find:

The width of the walkway.

Solution:

A cement walkway is added around the outside of the garden.

Let x be the width of the walkway.

The width of the garden with walkway = 10+2x

The length of the garden with walkway = 14+2x

Area of a rectangle is

Area=length\times width

Area of garden and the walkway together is

Area=(14+2x)\times (10+2x)

396=140+28x+20x+4x^2

396=140+48x+4x^2

396=4(35+12x+x^2)

Divide both sides by 4.

99=35+12x+x^2

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Splitting the middle term, we get

x^2+16x-4x-64=0

x(x+16)-4(x+16)=0

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(x+16)=0\text{ and }(x-4)=0

x=-16\text{ and }x=4

Width of walkway cannot be negative. So, x=4.

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The minimum is the smallest value of the function: -1. (not -2)

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The midline is the average of the minimum and maximum: (5-1)/2 = 2.

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