Answer:
A
Explanation:
Because the gravity and the mass of objects are proportionate
awnser : 6.02×1023 molcules
The percent yield for this reaction is 91%.
<u>Explanation</u>:
Ba(NO3)2 + Na2SO4 — > BaSO4 + 2NaNO3
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Assume that 0.45 mol of Ba(NO3)2 reacts with excess Na2SO4 to create 0.41 mol of BaSO4.
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Convert to grams of BaSO4 utilizing its molar mass (233.38 g/mol), which will be giving the actual yield.
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Actual Yield = 0.41 mol BaSO4 x (233.38 g BaSO4/1 mol BaSO4)
= 96 g BaSO4
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Beginning with 0.45 mol of Ba(NO3)2, compute the theoretical yield of BaSO4. Mole proportion of Ba(NO3)2 to BaSO4 is 1:1.
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0.45 mol Ba(NO3)2 x (1 mol BaSO4/1 mol Ba(NO3)2) x (233.38 g BaSO4/1 mol BaSO4) = 105 g BaSO4
% Yield = (Actual Yield/Theoretical Yield) x 100%
= (96/105) x 100%
= 91%.
Hi, i think the correct answer would be D .
Answer: 0.664 moles and 65.1 grams EDMENTUM USERS
Explanation: From the equation, we know that 1 mole of calcium phosphate produces 2 moles of phosphoric acid (H3PO4). So, if we know how many moles of calcium phosphate are present in 103 grams of Ca3(PO4)2, we can find the corresponding number of moles of H3PO4 that are produced during the reaction.
