Answer:
Mass = 0.008 g
Explanation:
Given data:
Volume of H₂ = 107 mL
Pressure = 104.8 KPa
Temperature = 30°C
Mass of H₂ present = ?
Solution:
Formula:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will convert the units of temperature, pressure and volume.
Temperature = 30+273 = 303 K
Volume of H₂ = 107 mL (107/1000= 0.107 L)
Pressure = 104.8 KPa (104.8/101 = 1.04 atm)
by putting values,
1.04 atm ×0.107 L = n× 0.0821 atm.L/ mol.K × 303 K
0.11 atm.L = n×24.87 atm.L/ mol
n = 0.11 atm.L / 24.87 atm.L/ mol
n = 0.004
Mass of H₂:
Mass = number of moles × molar mass
Mass = 0.004 mol × 2 g/mol
Mass = 0.008 g
