Answer:
The condensation of water occurs in Atmosphere.

Explanation:
As we know when water is heated it converts into vapors and vapors on cooling condense back into liquid water. Hence, the water present in Oceans (hydrosphere) on heating evaporates (remember evaporation takes place at any temperature) and move upward into the atmosphere. In atmosphere at high altitude the temperature drops (almost 18 °C) which causes the water vapors to condense hence, resulting in the formation of clouds which on precipitation causes rain fall.

8 0

4 years ago

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How many liters of HF can be made from 50.0 g of a 12.0M HF solution

aliina [53]

Answer:

Explanation:

The first thing we calculate are the moles: (50.0 g)/(20.0063 g/mol) =2.5 moles

Then we use the inverse formula for the molarity: (2.5 mol)/(12.0 M) = 0.208 L

My bad, I pressed the wrong button for answer!

5 0

3 years ago

The metabolic oxidation of glucose, C6H12O6, in our bodies produces CO2, which is expelled from our lungs as a gas.

enot [183]

Answer:

$\large \boxed{\text{21.6 L}}$

Explanation:

We must do the conversions

mass of C₆H₁₂O₆ ⟶ moles of C₆H₁₂O₆ ⟶ moles of CO₂ ⟶ volume of CO₂

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ: 180.16

C₆H₁₂O₆ + 6O₂ ⟶ 6CO₂ + 6H₂O

m/g: 24.5

(a) Moles of C₆H₁₂O₆

$\text{Moles of C$_{6}$H$_{12}$O}_{6} = \text{24.5 g C$_{6}$H$_{12}$O}_{6}\times \dfrac{\text{1 mol C$_{6}$H$_{12}$O}_{6}}{\text{180.16 g C$_{6}$H$_{12}$O}_{6}}\\\\= \text{0.1360 mol C$_{6}$H$_{12}$O}_{6}$

(b) Moles of CO₂

$\text{Moles of CO}_{2} =\text{0.1360 mol C$_{6}$H$_{12}$O}_{6} \times \dfrac{\text{6 mol CO}_{2}}{\text{1 mol C$_{6}$H$_{12}$O}_{6}} = \text{0.8159 mol CO}_{2}$

(c) Volume of CO₂

We can use the Ideal Gas Law.

pV = nRT

Data:

p = 0.960 atm

n = 0.8159 mol

T = 37 °C

(i) Convert the temperature to kelvins

T = (37 + 273.15) K= 310.15 K

(ii) Calculate the volume

$\begin{array}{rcl}pV &=& nRT\\\text{0.960 atm} \times V & = & \text{0.8159 mol} \times \text{0.082 06 L}\cdot\text{atm}\cdot\text{K}^{-1}\text{mol}^{-1} \times \text{310.15 K}\\0.960V & = & \text{20.77 L}\\V & = & \textbf{21.6 L} \\\end{array}\\\text{The volume of carbon dioxide is $\large \boxed{\textbf{21.6 L}}$}$

7 0

3 years ago

What is the net ion charge of beryllium? +2 -2 +1 -1

miss Akunina [59]

+2, because Beryllium is in the Group II of the periodic table.

Hope this helps!

8 0

3 years ago

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