Answer:
An element with 7 valence electrons will most likely be a halogen and gain an electron
Explanation:
Answer:
will form bonds between atoms. for more details are in the pic
Answer: A dilation with rule: ![(x,y)\to(\dfrac12x,\dfrac12y)](https://tex.z-dn.net/?f=%28x%2Cy%29%5Cto%28%5Cdfrac12x%2C%5Cdfrac12y%29)
Explanation:
A dilation is a non-rigid transformation that creates an image that is the same shape as the original but has a different size.
It uses a scale factor k such that
![(x,y)\to(kx,ky)](https://tex.z-dn.net/?f=%28x%2Cy%29%5Cto%28kx%2Cky%29)
(x,y)= coordinates of original figure
(kx,ky) = corresponding coordinate in the image.
To transform: A (3,-4) onto point A' (1.5,-2).
Using scale factor k=
, we have
![A(3,-4)\to A'(\dfrac12\times3, \dfrac12\times-4)=A'(1.5,-2)](https://tex.z-dn.net/?f=A%283%2C-4%29%5Cto%20A%27%28%5Cdfrac12%5Ctimes3%2C%20%5Cdfrac12%5Ctimes-4%29%3DA%27%281.5%2C-2%29)
Required rule: ![(x,y)\to(\dfrac12x,\dfrac12y)](https://tex.z-dn.net/?f=%28x%2Cy%29%5Cto%28%5Cdfrac12x%2C%5Cdfrac12y%29)
The final molarity of HCl is 2.284 M
We'll begin by listing what was given from the question. This is shown below:
Initial volume (V₁) = 5.56 mL
Initial Molarity (M₁) = 4.108 M
Final volume (V₂) = 5.56 + 4.44 = 10 mL
<h3>Final Molarity (M₂) =? </h3>
The final molarity of the HCl solution can be obtained by using the dilution formula as illustrated below:
<h3>M₁V₁ = M₂V₂</h3>
4.108 × 5.56 = M₂ × 10
22.84048 = M₂ × 10
Divide both side by 10
M₂ = 22.84048 / 10
<h3>M₂ = 2.284 M</h3>
Therefore, final molarity of the HCl solution is 2.284 M.
Learn more: brainly.com/question/6103588
Answer:
1. Alkali metals (group 1)
2. halogens (Group 17)
3. noble gasses (group 18)
Explanation:
1. alkali metals only have one valence electron meaning that they really want to lose that one valence electron to get a full octet.
2. halogens have 7 valence electrons meaning that they just need to gain 1 to get a full octet.
3. Nobel gasses already have a full octet meaning that they don't want to react. (atoms only react to get a full octet)
I hope this helps. Let me know if anything is unclear.