Answer : The correct option is, (A) 0.109 M
Solution : Given,
Mass of = 17 g
volume of solution = 974 ml
Molar mass of = 159.609 g/mole
Molarity : It is defined as the number of moles of solute present in one liter of solution.
Formula used :
where,
w = mass of (solute)
M = molar mass of
= volume of solution in liter
Now put all the given values in the above formula, we get the molarity of solution.
Therefore, the molarity of the solution is, 0.109 M
Answer: V=67.2 L
Explanation:
For this problem we will need to use the Ideal Gas Law.
Ideal Gas Law: PV=nRT
P=1.00 atm (STP)
V=?
n=3.00 mol
R=0.08206Latm/Kmol
T=273.15 K (STP)
To find V, we would manipulate the equation to V=nRT/P
With significan figures, our answer is V=67.2 L.
Answer: Molar concentration of the tree sap have to be 0.783 M
Explanation:
To calculate the concentration of solute, we use the equation for osmotic pressure, which is:
where,
= osmotic pressure of the solution = 19.6 atm
i = Van't hoff factor = 1 (for non-electrolytes)
R = Gas constant =
T = temperature of the solution =
Putting values in above equation, we get:
Thus the molar concentration of the tree sap have to be 0.783 M to achieve this pressure on a day when the temperature is 32°C