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ipn [44]
3 years ago
13

How does the junkyard magnet let go of metal?

Physics
1 answer:
klemol [59]3 years ago
7 0

Answer:

Wrecking yards employ extremely powerful electromagnets to move heavy pieces of scrap metal or even entire cars from one place to another. ... This creates a magnetic field around the coiled wire, magnetizing the metal as if it were a permanent magnet

Explanation:

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The total amount of force exerted on an object is called
ziro4ka [17]

Answer:

net force

Explanation:

net force is the total amount of force exerted on an object.

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3 years ago
Which statement is TRUE? Question 5 options: Waves travel at different speeds through different materials. Wave speed depends on
Sunny_sXe [5.5K]

Answer:

Waves move through different vmaterials

5 0
2 years ago
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PLS ANSWERR THIS QUESTION FOR ME !!
MA_775_DIABLO [31]

Explanation:

20 joule is your answer

Answer:

here

mass m =100kg

distance d=50m

acceleration due to gravity a =10m/s²

work =force×displacement

= ma/d=100×10/50=20joule

3 0
2 years ago
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What is significant about the primary colors of pigments?
ASHA 777 [7]

A. They can be mixed together to make almost any other color.

Explanation:

The most significant thing about primary colors is that they can be mixed together to form any other colors. Primary colors are red, blue and green. These are the three primary colors of light.

  • Other colors can derived from primary colors when making pigments.
  • If the the three primary colors are mixed together, white color is produced.
  • Secondary colors are the other colors produced by combining any two primary colors of light.
  • Two colors the produce white when mixed are complementary colors.

Learn more:

Color vision brainly.com/question/5661389

#learnwithBrainly

8 0
3 years ago
In the mobile m1=0.42 kg and m2=0.47 kg. What must the unknown distance to the nearest tenth of a cm be if the masses are to be
LuckyWell [14K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

Explanation:

From he question we are told that

    The first mass is   m_1 = 0.42kg

      The second mass is  m_2 = 0.47kg

From the question we can see that at equilibrium the moment about the point where the  string  holding the bar (where m_1 \ and \ m_2 are hanged ) is attached is zero  

   Therefore we can say that

               m_1 * 15cm  = m_2 * xcm

Making x the subject of the formula  

                x = \frac{m_1 * 15}{m_2}

                    = \frac{0.42 * 15}{0.47}

                     x = 13.4 cm

Looking at the diagram we can see that the tension T  on the string holding the bar where m_1  \  and   \ m_2 are hanged  is as a result of the masses (m_1 + m_2)

     Also at equilibrium the moment about the point where the string holding the bar (where (m_1 +m_2)  and  m_3 are hanged ) is attached is  zero

   So basically

          (m_1 + m_2 ) * 20  = m_3 * 30

          (0.42 + 0.47)  * 20 = 30 * m_3

 Making m_3 subject

          m_3 = \frac{(0.42 + 0.47) * 20 }{30 }

                m_3 = 0.59 kg

3 0
3 years ago
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