Answer:
0.7 kg m²
Explanation:
F = force exerted applied by muscle in a professional boxer = 2551 N
r = length of lever arm = 3.15 cm = 0.0315 m
α = angular acceleration of the forearm = 115 rad/s²
I = moment of inertia of the boxer's forearm
τ = Torque applied by muscle in a professional boxer
Torque is given as
τ = I α = r F
Inserting the values
I (115) = (0.0315) (2551)
I = 0.7 kg m²
Answer:
I₂ = 2.13 x 10⁻⁸ W/m²
Explanation:
given,
increase in sound level = 28.1 dB
frequency of the sound = 250 Hz
intensity = 3.3 x 10⁻¹¹ W/m²
Intensity delivered = ?
the difference of intensity level is give as






I₂ = 645.65 I₁
I₂ = 645.65 x 3.3 x 10⁻¹¹
I₂ = 2.13 x 10⁻⁸ W/m²
Answer:
D...............................
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