1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Zigmanuir [339]
3 years ago
13

Write a compound inequality for the graph below

Mathematics
1 answer:
Korolek [52]3 years ago
8 0

Your question is incomplete please provide exactly what graph you are talking about.

You might be interested in
Parallelogram RSTU is rotated 180° clockwise
julia-pushkina [17]

Answer:

Two pairs of parallel sides

Step-by-step explanation:

The given transformation performed on parallelogram RSTU = 180° clockwise rotation

Given that a rotation is a form of rigid transformation, the shape and size of the preimage RSTU will be equal to the the shape and size of the image R'S'T'U'

Therefore, RSTU ≅ R'S'T'U' and R'S'T'U' is also a parallelogram with two pairs of parallel sides.

4 0
3 years ago
Simplify 3^2 ⋅ 3^5<br><br> 3^7<br> 3^10<br> 9^7<br> 9^10
love history [14]
3^7 when you are multiplying numbers with the same base add the exponents.
3 0
3 years ago
Read 2 more answers
Point p’ (1,5) is the image of p (-3,1) under a translation<br><br> khan academy
GarryVolchara [31]

Answer:

<h2>X = \frac{-x}{3}</h2><h2>Y = 5y.</h2>

Step-by-step explanation:

We need to find the translation for which, (-3, 1) becomes (1, 5).

-3 will become 1, if it is divided by -3.

Hence, the translation for x axis is X = \frac{-x}{3}.

1 will become 5, when it is multiplied by 5.

Hence, The translation for y axis is Y = 5y.

6 0
3 years ago
Read 2 more answers
From a box containing 10 cards numbered 1 to 10, four cards are drawn together. The probability that their sum is even is 21 21
ankoles [38]

Answer:

Step-by-step explanation:

We know that between 1 to 10 there are 5 even and 5 odd numbers.

We could get 4 even cards , 4 odd cards or 2 odd and 2 even cards

Let´s check all this combinations

Case 1: When all 4 numbers are even:  

We are going to take 4 of the 5 even numbers in the box so we have

5C4=5

Case 2: When all 4 numbers are odd:  

We are going to take 4 of the 5 odd numbers in the box, so we have

5C4=5

Case 3: When 2 are even and 2 are odd:

We are giong to take 2 from 5 even and odd cards in the box so we have

 

5C2 * 5C2

Remember that we obtain the probability from

\frac{Number-of-favourable-Outcome}{Total-number-of-outcomes}

So we have the number of favourable outcomes but we need the Total cases for drawing four cards, so we have that:  

We are taking 4 of the 10 cards:

10C_4=210

Hence we have that the probability that their sum is even

\frac{5+5+100}{210}=\frac{11}{21}

8 0
2 years ago
Becky accepted a job as an inventory manager after being offered an $800 signing bonus. If she makes $23 an hour, which equation
dusya [7]
Y = 23x + 800 (Apex)

6 0
3 years ago
Other questions:
  • Write the equation of the line in point-slope form
    6·1 answer
  • What is the general term equation, a_n , for the arithmetic sequence 5, 1,–3, –7…and what is the 21st term of this sequence?
    5·1 answer
  • Out of a random sample of 330 apples, 25 are rated “AAA.” Estimate the number of apples that would be rated “AAA” in a crop of 5
    14·2 answers
  • Find the angle 0 between the vectors. u=(1, 1, 1, 0), v = (4, 4, 4, 4).
    8·1 answer
  • Decrease of 65% is the same as multiplying by what<br> percent?
    7·2 answers
  • cara played a card game using a deck of 52 cards after she dealt the same number of cards to 4 players she had 24 cards left ov
    15·1 answer
  • Your 3rd quarter final will be in April. The test will be 100 points total and contain 35 questions.
    8·1 answer
  • If two angles are complementary and one angle is 89º what is the measure of the other angle?
    7·1 answer
  • I NEED HELP!! THIS MY FINAL!
    13·1 answer
  • 3+7(0.7+1.3)<br> What is the answer and how to solve it?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!