Answer: waves transport energy, not water. As a wave crest passes, the water particles move in circular paths. The movement of the floating inner tube is simulacra to the movement of the water particles. Water particles rise as a wave crest approaches.
Explanation:
Answer:
a = 3.61[m/s^2]
Explanation:
To find this acceleration we must remember newton's second law which tells us that the total sum of forces is equal to the product of mass by acceleration.
In this case we have:
![F = m*a\\\\m=mass = 3.6[kg]\\F = force = 13[N]\\13 = 3.6*a\\a = 3.61[m/s^2]](https://tex.z-dn.net/?f=F%20%3D%20m%2Aa%5C%5C%5C%5Cm%3Dmass%20%3D%203.6%5Bkg%5D%5C%5CF%20%3D%20force%20%3D%2013%5BN%5D%5C%5C13%20%3D%203.6%2Aa%5C%5Ca%20%3D%203.61%5Bm%2Fs%5E2%5D)
Answer: Copper and oxygen
Explanation:
Copper and oxygen shares the ionic bond. As we know that ionic bond is the most strongest bond. Here is the order:
Hydrogen bond< Metallic bond< Ionic bond.
That means order in terms of increasing bond strength is :
Hydrogen and hydrogen< Copper and copper< Copper and oxygen.
Answer:
a) ![\alpha=0.5117\ rad.s^{-2}](https://tex.z-dn.net/?f=%5Calpha%3D0.5117%5C%20rad.s%5E%7B-2%7D)
b) ![\theta=8.4\ rad](https://tex.z-dn.net/?f=%5Ctheta%3D8.4%5C%20rad)
Explanation:
Given:
- initial rotational speed of phonograph,
![\omega_i=0\ rad.s^{-1}](https://tex.z-dn.net/?f=%5Comega_i%3D0%5C%20rad.s%5E%7B-1%7D)
- final rotational speed of phonograph,
![N_f=28\ rpm \Rightarrow \omega_f=2\pi\times\frac{28}{60} =2.932\ rad.s^{-1}](https://tex.z-dn.net/?f=N_f%3D28%5C%20rpm%20%5CRightarrow%20%5Comega_f%3D2%5Cpi%5Ctimes%5Cfrac%7B28%7D%7B60%7D%20%3D2.932%5C%20rad.s%5E%7B-1%7D)
- time taken for the acceleration,
![t=5.73\ s](https://tex.z-dn.net/?f=t%3D5.73%5C%20s)
a)
Now angular acceleration:
![\alpha=\frac{\omega_f-\omega_i}{t}](https://tex.z-dn.net/?f=%5Calpha%3D%5Cfrac%7B%5Comega_f-%5Comega_i%7D%7Bt%7D)
![\alpha=\frac{2.932-0}{5.73}](https://tex.z-dn.net/?f=%5Calpha%3D%5Cfrac%7B2.932-0%7D%7B5.73%7D)
![\alpha=0.5117\ rad.s^{-2}](https://tex.z-dn.net/?f=%5Calpha%3D0.5117%5C%20rad.s%5E%7B-2%7D)
b)
Using eq. of motion:
![\theta=\omega_i.t+\frac{1}{2} \alpha.t^2](https://tex.z-dn.net/?f=%5Ctheta%3D%5Comega_i.t%2B%5Cfrac%7B1%7D%7B2%7D%20%5Calpha.t%5E2)
![\theta=0+\frac{1}{2}\times 0.5117\times 5.73^2](https://tex.z-dn.net/?f=%5Ctheta%3D0%2B%5Cfrac%7B1%7D%7B2%7D%5Ctimes%200.5117%5Ctimes%205.73%5E2)
![\theta=8.4\ rad](https://tex.z-dn.net/?f=%5Ctheta%3D8.4%5C%20rad)