All categories

3 years ago

The battery of a flashlight develops 3 V, and the current through the bulb is 200 mA.What power is absorbed by the bulb?

Physics

1 answer:

Verizon [17]3 years ago

3 0

Answer : The power absorbed by the bulb is, 0.600 W

Explanation :

As we know that,

Power = Voltage × Current

Given:

Voltage = 3 V

Current = 200 mA = 0.200 A

Conversion used : (1 mA = 0.001 A)

Now put all the given values in the above formula, we get:

Power = Voltage × Current

Power = 3V × 0.200 A

Power = 0.600 W

Thus, the power absorbed by the bulb is, 0.600 W

You might be interested in

(b) A car of mass 3000 kg travels at a constant velocity of 5.0 m/s.

Tamiku [17]

Answer:

16.7 s

Explanation:

T= Vf - Vo a= F

a m

4,500 / 3000 = 1.5 (a)

30 - 5 / 1.5(a) = 16.7 s

4 0

3 years ago

In the diagram, the trough of the wave is shown by:

Kisachek [45]

Answer:

the correct representation of the trough is b

3 0

3 years ago

Five things that were invented by tesla? please answer!!!!

algol13

Answer:

remote control, neon and fluorescent lights, wireless transmission, computers, smartphones

Explanation:

6 0

2 years ago

Read 2 more answers

A car is being tested for safety by colliding it with a brick wall.The 1300 kg car is initially driving towards the wall at a sp

serg [7]

Answer:

44200 N

Explanation:

To calculate the average force exerted on the car, we will use the following equation

$\begin{gathered} Ft=\Delta p \\ Ft=m(v_f-v_i) \end{gathered}$

Where F is the average force, t is the time, m is the mass, vf is the final velocity and vi is the initial velocity of the car.

Replacing t = 0.5s, m = 1300 kg, vf = -2 m/s, and vi = 15 m/s and solving for F, we get

$\begin{gathered} F(0.5s)=(1300\text{ kg\rparen\lparen-2 m/s - 15 m/s\rparen} \\ F(0.5s)=(1300\text{ kg\rparen\lparen-17 m/s\rparen} \\ F(0.5s)=-22100\text{ kg m/s} \\ F=\frac{-22100\text{ kg m/s}}{0.5\text{ s}} \\ F=-44200\text{ N} \end{gathered}$

Therefore, the average force exerted on the car by the wall was 44200 N

4 0

11 months ago

A plane electromagnetic wave, with wavelength 2.8 m, travels in vacuum in the positive direction of an x axis. the electric fiel

Arte-miy333 [17]

Ok first you gotta know what they are actually even asking you.

Frequency = wavelengths per second
Angular Frequency = radians per second
Wave Number = wavelengths per meter
Angular Wave Number = radians per meter

Frequency is Easy, just divide the speed of light by the wavelength. This is your answer for A.

Angular frequency is how many radians per second the ELECTRIC FIELD moves through over one second. We know that there are 2π radians in one wavelength.

So to get the angular frequency just multiply the regular frequency by 2π (6.28) to get the frequency in terms of radians per second (instead of waves per second). This is your answer for B.

The wave number of a photon is how many waves per meter the photon moves through rather than waves per second, similar but different to the 'frequency' calculations above.

Simply find the waves per meter (1 meter divided by the wavelength) and multiply by 2π to get the radians per meter. this is your answer for C.

NOTE: make sure your units are all correct, wavelength in meters, frequency in Hz etc...

3 0

2 years ago