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nadya68 [22]
3 years ago
14

. A weather balloon is inflated to a volume of 2.2 x 103 L with 37.4 g of helium. What is the density of helium in grams per lit

er?. . A) 59 g/L. . B) 1.7 x 10-2 g/L. . C) 44.4 g/L
Physics
1 answer:
Margarita [4]3 years ago
6 0
That is the mst best eway to find its solution.
37.4/2.2*10^3 =  0.017 gm/liter or  1.7*10^-2
so we conclude that option b is sorrect
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As a ship comes into view over the horizon the top appears before the rest of the ship how does this demonstrate the earth is sp
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Since its a sphere, the top is seen first because its the tallest part if the ship. If the earth was flat, the whole ship would be seen.
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Vocabulary word for the total amount of charge in a closed system remains constant
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Answer:

i think this is it i dont know tho A conservation law stating that the total electric charge of a closed system remains constant over time, regardless of other possible changes within the system. "Conservation of charge." YourDictionary. LoveToKnow

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What is mean by combination reaction ?​​
mrs_skeptik [129]

\underline{\purple{\large \sf Combination \: reaction :-}}

Those reaction in which two or more substances combine to form a one new substance are called Combination reaction

In this reaction, We can add :

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\underline{\green{\large \sf For\: example :}}

\sf 2H_{2}  + O_{2} \:  \underrightarrow{Combination} \: 2H_{2}o

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3 years ago
The speed of light in a vacuum is approximately 2.99 × 108 m/s, and the speed of light through a piece of glass is approximately
labwork [276]

The answer is 1.52.

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6 0
3 years ago
Read 2 more answers
To test the performance of its tires, a car travels along a perfectly flat (no banking) circular track of radius 130 m. The car
marysya [2.9K]

Answer:

0.739

Explanation:

If we treat the four tire as single body then

W ( weight of the tyre ) =  mass × acceleration due to gravity (g)

the body has a tangential acceleration = dv/dt = 5.22 m/s², also the body has centripetal acceleration to the center = v² / r

where v is speed 25.6 m/s and r is the radius of the circle

centripetal acceleration = (25.6 m/s)² / 130 = 5.041 m/s²

net acceleration of the body = √ (tangential acceleration² + centripetal acceleration²) = √ (5.22² + 5.041²) = 7.2567 m/s²

coefficient of static friction between the tires and the road = frictional force / force of normal

frictional force = m × net acceleration / m×g

where force of normal = weight of the body in opposite direction

coefficient of static friction = (7.2567 × m) / (9.81 × m)

coefficient of static friction = 0.739

4 0
3 years ago
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