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nadya68 [22]
3 years ago
14

. A weather balloon is inflated to a volume of 2.2 x 103 L with 37.4 g of helium. What is the density of helium in grams per lit

er?. . A) 59 g/L. . B) 1.7 x 10-2 g/L. . C) 44.4 g/L
Physics
1 answer:
Margarita [4]3 years ago
6 0
That is the mst best eway to find its solution.
37.4/2.2*10^3 =  0.017 gm/liter or  1.7*10^-2
so we conclude that option b is sorrect
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If a hockey player starts from rest and accelerates at a rate of 2.1 m/s², how long does it take him to skate 30 m?
Vlada [557]

Answer:

its A i think im not sure tho

Explanation:

5 0
3 years ago
if you were to increase either mass or speed by a unit of 1 in a joules calculation, which would give you more energy?
musickatia [10]

Answer:increasing any of them, either mass or speed by 1unit will cause an increase in energy,

Explanation:

By increasing any of them, either mass or speed will cause an increase in energy.

Because kinetic energy is proportional to mass and also directly proportional to velocity

8 0
3 years ago
1. How much heat must be absorbed by 375 grams of water to raise its
antiseptic1488 [7]

Answer:

39225J

Explanation:

Given parameters:

Mass of water  = 375grams of water

Change in temperature  = 25°C

Specific heat capacity of water  = 4.184J/g°C

Unknown:

Amount of heat absorbed  = ?

Solution:

To solve this problem, we use the expression below:

      H  = m c Ф  

H is the heat absorbed

m is the mass

c is the specific heat capacity

Ф is the change in temperature

  Insert the parameters and solve;

      H  = 375 x 4.184 x (25) = 39225J

5 0
2 years ago
If you pull on something to the right with a force of 50 N and I pull on the same object to the left with a force of 60 N, what
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7 0
3 years ago
Even when the head is held erect, as in the figure below, its center of mass is not directly over the principal point of support
alexandr1967 [171]

We are asked to determine the force required by the neck muscle in order to keep the head in equilibrium. To do that we will add the torques produced by the muscle force and the weight of the head. We will use torque in the clockwise direction to be negative, therefore, we have:

\Sigma T=r_{M\perp}(F_M)-r_{W\perp}(W)

Since we want to determine the forces when the system is at equilibrium this means that the total sum of torque is zero:

r_{M\perp}(F_M)-r_{W\perp}(W)=0

Now, we solve for the force of the muscle. First, we add the torque of the weight to both sides:

r_{M\perp}(F_M)=r_{W\perp}(W)

Now, we divide by the distance of the muscle:

(F_M)=\frac{r_{W\perp}(W)}{r_{M\perp}}

Now, we substitute the values:

F_M=\frac{(2.4cm)(50N)}{5.1cm}

Now, we solve the operations:

F_M=23.53N

Therefore, the force exerted by the muscles is 23.53 Newtons.

Part B. To determine the force on the pivot we will add the forces we add the vertical forces:

\Sigma F_v=F_j-F_M-W

Since there is no vertical movement the sum of vertical forces is zero:

F_j-F_M-W=0

Now, we add the force of the muscle and the weight to both sides to solve for the force on the pivot:

F_j=F_M+W

Now, we plug in the values:

F_j=23.53N+50N

Solving the operations:

F_j=73.53N

Therefore, the force is 73.53 Newtons.

8 0
10 months ago
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