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Mekhanik [1.2K]
3 years ago
7

a force 10N drags a mass 10 kg on a horizontal table with acceleration 0.2m\s. If the acceleration due to gravity is 10m\s2, a c

oefficient of friction between the moving mass and a table is?​
Physics
1 answer:
kakasveta [241]3 years ago
7 0

Answer:

Explanation: 0.02

Recall: μ mg = ma

μ = ?

m = 10N

g = 10m\s2

a = 0.2m\s

Substituting the values , we have

μ x 10 x 10 = 10 x 0.2

100  μ = 2

μ = 2/100

μ = 1/50

μ = 0.02

μ = 0.02

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A 48.0-kg astronaut is in space, far from any objects that would exert a significant gravitational force on him. He would like t
marusya05 [52]

Answer:

The astronaut is moving at a speed of 0.36m/s

Explanation:

Speed here corresponds to velocity

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∑momentum (M) = ∑astronaut momentum

∑M = ∑astronaut M

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48 × velocity of astronaut= 3.6 + 6.4 + 7.2

48 × velocity of astronaut= 17.2

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5 0
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Which quantity may be calculated directly using Newton's second law of motion?
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Answer:

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Answer:

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Through Brahe's astronomical measurements and Kepler's own drawings of the geometrical relationship between the Sun and Mars in various parts of the planet's orbit, Kepler discovered that planets moved faster when they were closer to the Sun.

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