At what temperature is the fahrenheit scale reading equal to twice that of the celsius?

The sun continuously radiates energy into space in all directions. Some of the sun's energy is intercepted by the Earth. The ave

8_murik_8 [283]

B. The Earth radiates an amount of energy into space equal to the amount it receives.

Part of the solar energy is reflected by the Earth into space, this is known as albedo. The other part of the energy radiated by the Earth in the form of infrared radiation, is absorbed by the greenhouse gases, which cause most of this infrared radiation to be emitted into space. Therefore, the net flow of energy is zero.

7 0

3 years ago

Astronauts on a distant planet set up a simple pendulum of length 1.2 m. The pendulum executes simple harmonic motion and makes

Iteru [2.4K]

Answer:

If you use P = 2 * pi * (L / g)^1/2 for the period of the simple pendulum

g = 4 * pi^2 * 1.2 / 2.8^2 = 6.04 m/s2

Note: omega = 2 pi * f = 2 pi / P and omega = (g / L)^1/2

7 0

3 years ago

When decreasing electromagnetic radiation there is a(n)_______relationship between wavelength and frequency and the greater the

IceJOKER [234]

Answer:

Inverse proportion, greater

Explanation:

The relation between wavelength (λ) and frequency (ν) is given by

$\nu = \frac{c}{\lambda }$

Where $c$ speed of light in vacuum.

We can see from this equation that wavelength and frequency are related inversely.

Now,

$E= h \nu$

Where 'E' is energy of electromagnetic radiation and 'h' is Planck's constant.

We can see from this equation that greater frequency (ν) will give greater electromagnetic radiation (E). As they are directly proportional.

Hence,

When decreasing electromagnetic radiation there is a(n) Inverse proportion relationship between wavelength and frequency and the greater the frequency, the greater energy the electromagnetic radiation has

5 0

3 years ago

Science

Temka [501]

When a light wave encounters an object, they are either transmitted,reflected,absorbed,refracted,diffracted, or scattered depending on the wave

3 0

3 years ago

A mountain lion jumps to a height of 3.25 m when leaving the ground at an angle of 43.2°. What is its initial speed (in m/s) as

miss Akunina [59]

Recall that

${v_f}^2={v_i}^2+2a\Delta y$

where $v_i$ and $v_f$ are the lion's initial and final vertical velocities, $a$ is its acceleration, and $\Delta y$ is the vertical displacement.

At its maximum height, the lion has 0 vertical velocity, so we have

$0={v_i}^2-2gy_{\rm max}$

where <em>g</em> is the acceleration due to gravity, 9.80 m/s², and we take the starting position of the lion on the ground to be the origin so that $\Delta y=y_{\rm max}-0=y_{\rm max}$ .

Let <em>v</em> denote the initial speed of the jump. Then

$v_i=v\sin(43.2^\circ)=\sqrt{2\left(9.80\dfrac{\rm m}{\mathrm s^2}\right)(3.25\,\mathrm m)}\implies\boxed{v\approx11.7\dfrac{\rm m}{\rm s}}$

6 0

3 years ago