To determine the number of cubes he needs to fill the box (this is assuming the cubes are 1 in cubes, he would need to calculate the volume of the box. To find the volume he would multiply the length by the width by the height. This would be 5 in x 6 in x 7 in. The volume is 210 cubic inches, so he could fill it with 210 one inch cubes.
Answer:
9+20t
Step-by-step explanation:
Look at the terms and see which has t and which is a number when you see like terms, add them or subtract them together to get like terms.
When atleast one dice shows a 6 the possible outcomes will be:
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)
(1,6), (2,6), (3,6), (4,6), (5,6)
Thus there are 11 total possible outcomes.
Among these outcomes, the sum of numbers greater than or equal to 9 can be obtained from:
(6,3), (6,4), (6,5), (6,6), (3,6), (4,6), (5,6)
This means there are 7 outcomes with sum greater than or equal to 9.
Thus, Probability of rolling a number greater than or equal to 9 with atleast one dice showing a 6 = 9/11
So, option A gives the correct answer
