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Darina [25.2K]
3 years ago
10

Help please!!! Idk the answer.. if anyone knows then will u help me please!!! I will mark as BRAINLIEST​

Mathematics
2 answers:
serious [3.7K]3 years ago
7 0

Answer:

which one?

Step-by-step explanation:

Alenkasestr [34]3 years ago
3 0

Answer:

q9:20cm q10:17 dice can fit in and you have 4cm3 space remaining

Step-by-step explanation:

1L= 1000cm3

base=50cm2

base=5x10

1000/50=20cm

height =20 cm

5x10x20=1000cm3=1L

Question 10:dice=2x2x2=8cm3

box=5x4x7=140cm3

answer=140/8

answer=17.5 meaning we can fit 17 full dice into the box

The space we have left is 4cm3

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Fine the distance d(A,B)between Points A and B. A(4,-4);B(4,4)
Mariulka [41]

Answer:

Distance: 8

Step-by-step explanation:

d = sqrt [(x-x)^2 + (y-y)^2]

d = sqrt [(4-4)^2 + (-4-4)^2]

d = sqrt(0) + (-8)^2

d = sqrt 64 = 8

7 0
3 years ago
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Rewrite the equation y=2|x−3|+5 as two linear functions f and g with restricted domains.
vesna_86 [32]

The absolute value transforms a negative number into a positive number.

For example

Let z be a real number, then:

| z | It will always be a positive number.

This means that:

If z is a negative number, then:

| z | = -z

If z is a positive number, then:

| z | = z

This means that for the expression the expression y = 2 | x-3 | +5

When x-3 > 0 then:

| x-3 | = x-3

When x-3 < 0 then:

| x-3 | = - (x-3)

Then we can divide the expression into two functions f (x) and g (x).

f (x) = 2 (x-3) +5

f (x) = 2x-6 + 5

f (x) = 2x-1

For

(x-3) \geq 0\\ x \geq 3


g (x) = 2 (-x + 3) +5

g (x) = -2x + 6 + 5

g (x) -2x +11

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x < 3

8 0
3 years ago
Solve for x y=c(x+b)
sergeinik [125]

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3 years ago
You know that y is a normally distributed variable with a variance of 9. You do not know its mean. You collect some data. For ea
Dima020 [189]

Answer:

a)

CI = ( 1.2718, 8.0614 )

Since value 2 is contained within Confidence Interval, fail to Reject H₀

b)

CI = ( -2.2296, 3.0296 )

Since value 2 is contained within Confidence Interval, fail to Reject H₀

c)

CI = ( 0.2962, 4.4538 )

Since value 2 is contained within Confidence Interval, fail to Reject H₀

Step-by-step explanation:

Given that;

Variance σ² = 9

so standard deviation σ = √9 = 3

with 95% confidence interval in each case. thus, The Z value for 95% confidence is Z = 1.96

Null Hypotheses  H₀ : μ = 2

Now

a)  (8,1,5)

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n = 3

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so CI = ( 1.2718, 8.0614 )

Since value 2 is contained within Confidence Interval, fail to Reject H₀

b)  (8,1,5,-4,-8)  

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CI = 0.4 ± 2.6296

so CI = ( -2.2296, 3.0296 )

Since value 2 is contained within Confidence Interval, fail to Reject H₀

c)  (8,1,5,-4,-8,4,8,5)

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n = 8

Confidence Interval CI = x" ± ( z × σ/√n )

CI = 2.375 ± ( 1.96 × 3/√8 )

CI = 2.375 ± 2.0788

so CI = ( 0.2962, 4.4538 )

Since value 2 is contained within Confidence Interval, fail to Reject H₀

8 0
3 years ago
What is the mean snd median
dmitriy555 [2]

Mean is when u add all the numbers up and then divide how many numbers there are e.g 22 + 1 + 3=

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