Answer:
<h2>3.6°</h2>
Step-by-step explanation:
The question is incomplete. Here is the complete question.
Find the angle between the given vectors to the nearest tenth of a degree.
u = <8, 7>, v = <9, 7>
we will be using the formula below to calculate the angle between the two vectors;
is the angle between the two vectors.
u = 8i + 7j and v = 9i+7j
u*v = (8i + 7j )*(9i + 7j )
u*v = 8(9) + 7(7)
u*v = 72+49
u*v = 121
|u| = √8²+7²
|u| = √64+49
|u| = √113
|v| = √9²+7²
|v| = √81+49
|v| = √130
Substituting the values into the formula;
121= √113*√130 cos θ
cos θ = 121/121.20
cos θ = 0.998
θ = cos⁻¹0.998
θ = 3.6° (to nearest tenth)
Hence, the angle between the given vectors is 3.6°
Answer:
C. 97.5 yd
Step-by-step explanation:
The distance between Marsha, the ball and the tee for the fourth hole, forms a triangle.
Thus, the distance between Marsha's ball and the hole can be calculated using the Cosine formula below:
c² = a² + b² - 2abcos(C)
Where,
c = distance between Marsha's ball and the hole = ?
a = distance between the tee for the fourth hole and the tee = 300 yd
b = distance between tee and the hole = 255 yd
C = 18°
c² = 300² + 255² - 2(300)(255)cos(18)
c² = 90000 + 65025 - 153000 × 0.951
c² = 155025 - 145503
c² = 9522
c = √9522 ≈ 97.5
c = distance between Marsha’s ball and the hole = 97.5 yd (nearest tenth)
The answer is going to be A.
Shadow 1 / Height 1 = Shadow 2 / Height 2
Answer: MP=(1,1)
Step-by-step explanation:
-2+4=2 -3+5=2
2/2=1
Answer:
2a(7b+5)
Step-by-step explanation:
yeah-ya....... right?
