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pantera1 [17]
2 years ago
13

Which methods could be used to dilute a solution of sodium chloride

Chemistry
1 answer:
Brrunno [24]2 years ago
8 0

Answer:

hi how are you doing today Jasmine

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The term used to describe the rapid release of bubbles from a liquid is _____
aksik [14]
The term used to describe the rapid release of bubbles, or rapid release of a gas from a liquid or a solution is called Effervescence.  The bubbling of a solution is due to the escape of a gas which may be from a chemical reaction, as in fermenting liquid, or by coming out of a solution after having been under pressure, as in a carbonated drink. For example; soda, champagne among others.
5 0
3 years ago
The Michaelis constant for pancreatic lipase is 5 mM. At 60 C, lipase is subject to deactivation with a half-life of 8 min. Fat
Dmitriy789 [7]

Explanation:

According to the given data, we will calculate the following.

 Half life of lipase t_{1/2} = 8 min x 60 s/min

                                       = 480 s

Rate constant for first order reaction is as follows.

         k_{d} = \frac{0.6932}{480}

                        = 1.44 \times 10^{-3}s^{-1}


Initial fat concentration S_{o} = 45 mol/m^{3}

                                                = 45 mmol/L

Rate of hydrolysis V_m_{o} = 0.07 mmol/L/s

Conversion X = 0.80

Final concentration (S) = S_{o} (1 - X)

                                      = 45 (1 - 0.80)

                                      = 9 mol/m^{3}

or,                                  = 9 mmol/L

It is given that K_{m} = 5mmol/L

Therefore, time taken will be calculated as follows.

                    t = -\frac{1}{K_{d}}ln[1 - \frac{K_{d}}{V}{K_{M} ln (\frac{S_{o}}{S}) + (S_{o} - S)]

Now, putting the given values into the above formula as follows.

            t = -\frac{1}{K_{d}}ln[1 - \frac{K_{d}}{V}{K_{M} ln (\frac{S_{o}}{S}) + (S_{o} - S)]  

             = -\frac{1}{1.44 \times 10^{-3}s^{-1}}ln[1 - \frac{1.44 \times 10^{-3}s^{-1}}{0.07 mmol/L/s
}{K_{M} ln (\frac{45 mmol/L
}{9 mmol/L
}) + (45 mmol/L - 9 mmol/L
)]

              = 1642.83 s \times \frac{1 min}{60 sec}

              = 27.38 min

Therefore, we can conclude that time taken by the enzyme to hydrolyse 80% of the fat present is 27.38 min.

6 0
3 years ago
100 points right here first come first serve. amos thejonah2016
Kisachek [45]

Answer:

siya at ako ayieeeeeeeeee

7 0
3 years ago
Chem help what's the answer to 8 and why will give brainliest​
laiz [17]

avogadros law states that under constant temp n pressure, volume of a gas is directly proportional to amount of gas

amount of gas1 = 352millimoles

amount of gas2 = 352+100 = 452millimoles

new vol = old vol x 452/352 = 25.2 x 452/352

= 32.4 mL

4 0
3 years ago
Read 2 more answers
Convert 23.92inHg to Pa.
andriy [413]

Answer:

3189.07Pa

Explanation:

The conversion of 23.92mmH to Pa can be achieved in the following way:

760mmHg = 101325Pa

23.92mmHg = (23.92x101325)/760 = 3189.07Pa

5 0
3 years ago
Read 2 more answers
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