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pantera1 [17]
3 years ago
13

Which methods could be used to dilute a solution of sodium chloride

Chemistry
1 answer:
Brrunno [24]3 years ago
8 0

Answer:

hi how are you doing today Jasmine

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The following charges on individual oil droplets were obtained during an experiment similar to Millikan's. Determine a charge fo
RSB [31]

Answer:

- 1.602 x 10⁻¹⁹coulombs

Explanation:

Charge on individual oil droplet would be multiple of charge on one electron . So we will find out the minimum common factor of given individual charges that is the LCM of all the charges given.

LCM of given charges like 3.204 , 4.806 ,8.01 and 14.42 . We have neglected the power of ten( 10⁻¹⁹)  because it is  already a common factor to all.

The LCM  is 1.602 . So charge on electron is 1.602 x 10⁻¹⁹.

4 0
4 years ago
If a lab requires each a lab group (3 students) to have 25 ml of a solution and it takes 15 grams of AgNO₃ cuprous nitrate, to m
pochemuha

Answer:

0.375 grams are needed to make 25 mL solution.

Explanation:

Mass of AgNO_3 cuprous nitrate required to make 1 l of solution = 15 g.

1 L = 1000 mL

Mass of AgNO_3 cuprous nitrate required to make 1000 mL of solution = 15 g

Mass of AgNO_3 cuprous nitrate required to make 1 mL of solution:

=\frac{15}{1000} g

Mass of AgNO_3 cuprous nitrate required to make 25 mL of solution:

=\frac{15}{1000} \times 25 g=0.375 g

0.375 grams are needed to make 25 mL solution.

4 0
3 years ago
When does an object have an overall positive charge???
mars1129 [50]
It has an excess of electrons
the nuclei of its atoms are positively charged
it has a deficiency of electrons
the electrons of its atoms are positively charged
4 0
3 years ago
Read 2 more answers
How much energy is required to melt 2 kg of gold? Use the table below and this equation.
Lostsunrise [7]

Answer:

A. 125.6 kJ

Explanation:

ap*x

4 0
3 years ago
PLEASE HELP!!!
telo118 [61]

Answer:

4.62 atm

Explanation:

To find the missing pressure, you need to use the Combined Gas Law equation:

P₁V₁ / T₁ = P₂V₂ / T₂

In this equation, "P₁", "V₁", and "T₁" represent the initial pressure, volume, and temperature. "P₂", "V₂", and "T₂" represent the final pressure, volume, and temperature.

P₁ = 8.01 atm                      P₁ = ? atm

V₁ = 715 mL                        V₁ = 963 mL

T₁ = 67 °C                           T₁ = 52 °C

P₁V₁ / T₁ = P₂V₂ / T₂

(8.01 atm)(715 mL) / 67 °C = P₂(963 mL) / 52 °C

85.47985 = P₂(963 mL) / 52 °C

4444.952 = P₂(936 mL)

4.62 atm = P₂

4 0
2 years ago
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