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2 years ago

A sample of silver (Ag) contains 3.011x1023 atoms. How much does this

Chemistry

1 answer:

Ugo [173]2 years ago

3 0

Answer:

53.93 g Ag

Explanation:

3.011x1023 atoms Ag x <u> 1 mole Ag </u> x <u>107,8683 grams</u> =

6.022x $10^{23}$ atoms 1 mole Ag

use the periodic table fo find Ag atomic mass and use Avogadro´s number

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What did electrons from the ionized air do to the oil drops?

Neko [114]

Answer:

The famous oil drop experiment exploits that fact that an oil drop in an electronic field will get negative charge accumulation which can be balanced and observed in order to determine the charge of an electron.

6 0

2 years ago

Read 2 more answers

A new grill has a mass of 30.0 kg. you put 1.5 kg of charcoal in the grill. you burn all the charcoal and the grill has a mass o

atroni [7]

The reaction for burning of charcoal or complete combustion is as follows:

$C(s)+O_{2}(g)\rightarrow CO_{2}(g)$

From the above balanced reaction, 1 mole of carbon releases 1 mole of $CO_{2}$ gas.

Converting mass of charcoal into moles as follows:

$n=\frac{m}{M}$

Molar mass of pure carbon is 12 g/mol thus,

$n=\frac{1.5\times 10^{3} g}{12 g/mol}=125mol$

The same moles of $CO_{2}$ is released. Converting these moles into mass as follows:

m=n×M

Molar mass of $CO_{2}$ is 44 g/mol thus,

$m=125mol\times 44 g/mol=5.5\times 10^{3}g$

Converting mass into kg,

$1g=10^{-3}kg$

Thus, total mass of gas released is 5.5 kg.

7 0

2 years ago

Plants produce a variety of substances:food,flavoring,drugs,poisons.this is a result of

tatuchka [14]

Answer:

Synthesis

Explanation:

They synthesize these chemicals

7 0

2 years ago

A 0.2722 g sample of a pure carbonate, X n CO 3 ( s ) , was dissolved in 50.0 mL of 0.1200 M HCl ( aq ) . The excess HCl ( aq )

Alex73 [517]

Answer:

0.00369 moles of HCl react with carbonate.

Explanation:

Number of moles of HCl present initially = $\frac{0.1200}{1000}\times 50.0$ moles = 0.00600 moles

Neutralization reaction (back titration): $NaOH+HCl\rightarrow NaCl+H_{2}O$

According to above equation, 1 mol of NaOH reacts with 1 mol of 1 mol of HCl.

So, excess number of moles of HCl present = number of NaOH added for back titration = $\frac{0.0980}{1000}\times 23.60$ moles = 0.00231 moles

So, mole of HCl reacts with carbonate = (Number of moles of HCl present initially) - (excess number of moles of HCl present) = (0.00600 - 0.00231) moles = 0.00369 moles

Hence, 0.00369 moles of HCl react with carbonate.

3 0

2 years ago

Use the drop-down menus to rank the boiling points of the following hydrocarbons. Use a "1" to indicate

sertanlavr [38]

Answer:

1. 4

2. 2

3. 3

4. 1

Explanation: just did it on edge 2021

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2 years ago