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iVinArrow [24]
3 years ago
8

The table below contains characteristics of four different elements. Characteristics of Four Elements Element Number of Protons

Number of Valence Electrons 1 ca 4 2. 11 1 1 3 18 8 4 37 1 1 What conclusion can be made from the information above? Element 3 is a metal and Element 1 is a metalloid. Element 2 is the same element as Element 3. Element 1 has very similar chemical properties as Element 4. Element 2 has very similar chemical properties as Element 4.​

Chemistry
1 answer:
Katarina [22]3 years ago
5 0

Answer:

The correct option is "Element 2 has very similar chemical properties as Element 4"

Explanation:

Both element 2 and element 4 have the same number of valence electrons; meaning they will be found in the same group (group 1) of the periodic table. Elements in the same group of the periodic table exhibit similar chemical properties. For confirmation, element 2 is sodium (based on the atomic number of 11 provided) while element 4 is rubidium (based on the atomic number of 37 provided) - the two elements are found in group 1 of the periodic table.

NOTE: Number of protons is the same as atomic number

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1 pts
soldier1979 [14.2K]

Answer:

144 g

Explanation:

Use the mole ratio of 4 mol CO2 for every 9 mol O2 to convert from mol O2 to mol CO2. Then use the molar mass of CO2 to convert from mol of CO2 to grams of CO2.

7.34 mol O2 • (4 mol CO2 / 9 mol O2) • (44.01 g CO2 / 1 mol CO2) = 144 g CO2

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3 years ago
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What is the change of state that occurs in the condenser
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3 years ago
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Explain how using dimensional analysis could have prevented this crash
emmainna [20.7K]
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(m/s)*(s) = m

So, you would know that the solution would be 5*2 because it yields the unit for distance. 

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4 0
4 years ago
Which property provides the best evidence that the unknown substance is a solid
agasfer [191]
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7 0
4 years ago
For the following reaction, if 19.7 g of H2, is reacted with excess CO in the laboratory, and 144.5 g of CH3OH is produced, what
GuDViN [60]

Step 1

<em>The reaction involved:</em>

CO + 2 H2 → CH3OH (completed and balanced)

------------

Step 2

<em>Data provided:</em>

19.7 g H2 (the limiting reactant)

Excess reactant = CO

144.5 g CH3OH = actual yield

----

<em>Data needed:</em>

The molar masses of:

H2) 2.00 g/mol

CH3OH) 32.0 g/mol

-----------

Step 3

The theoretical yield:

By stoichiometry,

CO + 2 H2 → CH3OH (The molar rate between H2 and CH3OH = 2:1)

2 x 2.00 g H2 --------- 32.0 g CH3OH

19.7 g H2 --------- X

X = 19.7 g H2 x 32.0 g CH3OH/2 x 2.00 g H2

X = 157.6 g CH3OH (The theoretical yield)

-----------

Step 4

The % yield is defined as follows:

\begin{gathered} \text{ \%yield = }\frac{Actual\text{ yield}}{Theoretical\text{ yield}}x100\text{ } \\ \text{ \%yield = }\frac{144.5\text{ g}}{157.6\text{ g}}x100\text{ = 91.7 \% = 92 \% approx.} \end{gathered}

Answer: d. 93% (it is the nearest value in comparison to my result)

6 0
2 years ago
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