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hoa [83]
3 years ago
5

A bus travels 20km in 30 min what is the average speed of the bus

Chemistry
2 answers:
Mamont248 [21]3 years ago
8 0

Answer:

average speed=distance/time

speed=20/30

speed=2/3

STatiana [176]3 years ago
5 0

Answer:

40km/h

Explanation:

v=20km/0.5h=40km/h.

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How does 0.5 m sucrose (molecular mass 342) solution compare to 0.5 m glucose (molecular mass 180) solution?
mash [69]

Answer : Both solutions contain 3.011 X 10^{23} molecules.

Explanation : The number of molecules of 0.5 M of sucrose is equal to the number of molecules in 0.5 M of glucose. Both solutions contain 3.011 x 10^{23} molecules.

Avogadro's Number is  N_{A} =  6.022 X 10^{23} which represents particles per mole and particles may be typically molecules, atoms, ions, electrons, etc.

Here, only molarity values are given; where molarity is a measurement of concentration in terms of moles of the solute per liter of solvent.

Since each substance has the same concentration, 0.5 M, each will have the same number of molecules present per liter of solution.

Addition of molar mass for individual substance is not needed. As if both are considered in 1 Liter they would have same moles which is 0.5.

We can calculate the number of molecules for each;

Number of molecules  = N_{A} X M;

∴  Number of molecules =  6.022 X 10^{23} X 0.5 mol/L X 1 L which will be  = 3.011 X 10^{23}

Thus, these solutions compare to each other in that they have not only the same concentration, but they will have the same number of solvated sugar molecules. But the mass of glucose dissolved will be less than the mass of sucrose.

7 0
3 years ago
Read 2 more answers
Styrofoam has a density of 0.075 g/mL. What is the volume of 21.80 g of Styrofoam?
LekaFEV [45]

The answer is 290.66 mL

Explanation:

The density of any substance including styrofoam is determined by two main factors: mass (atoms in the substance) and volume (space occupied). Moreover, the volume or mass of the substance can be calculated by using the density as these variables are related. Below I show the process:

density = mass / volume

mass = density x volume

volume = mass / density

volume = 21.80 g / 0.075 g/mL

volume = 290.66 mL

4 0
3 years ago
The elements chlorine and iodine have similar chemical properties because they _____. Group of answer choices have the same numb
worty [1.4K]

Answer:

Have the same number of electrons in their outer energy levels

Explanation:

Elements in the same group have similar chemical properties because they have the same number of valence electron(s) in their outermost shell.

Chlorine and Iodine have similar chemical properties because they have the same number of valence electron in their outermost shell. This can be seen from their electronic configuration as shown below:

Cl (17) => 1s² 2s²2p⁶ 3s²3p⁵

I (53) => [Kr] 4d¹⁰ 5s²5p⁵

From the above illustration:

Outer shell of Cl (3s²3p⁵) = 2 + 5 = 7 electrons

Outer shell of I (5s²5p⁵) = 2 + 5 = 7 electrons

Since they have the same number of valence electrons, therefore, they will have similar chemical properties.

7 0
3 years ago
A 2.89 g sample of a metal chloride, MCl2, is dissolved in water and treated with excess aqueous silver nitrate. The silver chlo
dsp73

Answer:

58.0 g/mol

Explanation:

The reaction that takes place is:

  • MCl₂ + 2AgNO₃ → 2AgCl + M(NO₃)₂

First we <u>calculate how many moles of silver chloride</u> were produced, using its <em>molar mass</em>:

  • 6.41 g AgCl ÷ 143.32 g/mol = 0.0447 mol AgCl

Then we <u>convert AgCl moles into MCl₂ moles</u>, using the <em>stoichiometric ratio</em>:

  • 0.0447 mol AgCl * \frac{1molMCl_2}{2molAgCl} = 0.0224 mol MCl₂

Now we<u> calculate the molar mass of MCl₂</u>, using the original<em> mass of the sample</em>:

  • 2.86 g / 0.0224 mol = 127.68 g/mol

We can write the molar mass of MCl₂ as:

  • Molar Mass MCl₂ = Molar Mass of M + (Molar Mass of Cl)*2
  • 127.68 g/mol = Molar Mass of M + (35.45 g/mol)*2

Finally we<u> calculate the molar mass</u> of M:

  • Molar Mass of M = 57 g/mol

The closest option is 58.0 g/mol.

6 0
3 years ago
Measure the length of the line within the amount of uncertainty allowed. (Note: You may need to convert centimeters to millimete
grigory [225]
A. 3.6 cm
B.22.0 mm
C.1.25cm
D.7 mm
8 0
3 years ago
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